Boron has two isotopes B1055B10 and B1155B11. If atomic weight of Boron is 10.81 then ratio of B1055B10 to B1155B11in nature will be:
1. 15 : 16
2. 19: 81
3. 81 : 19
4. 20: 53
1. | 8926Kr8926Kr | 2. | 8936Kr8936Kr |
3. | 9026Sr9026Sr | 4. | 8938Sr8938Sr |
XmnnXm emitted one αand2 βαand2 β particles, then it will become:
1. Xm-4nnXm−4
2. Xm-1n-1n−1Xm−1
3. Zm-4nnZm−4
4. None of these
For the given reaction, the particle X is:
116C→115B+β++X
1. neutron
2. anti-neutrino
3. neutrino
4. proton
1. | Liquid droplet theory. |
2. | Yukawa π-meson theory. |
3. | Independent particle model of the nucleus. |
4. | Proton-proton cycle. |
Which rays contain (+ve) charged particle:
1. α-rays
2. β-rays
3. γ-rays
4. X-rays
If X(n, α ) converts into L73i, then X will be:
1. B105
2. B95
3. B114e
4. H42e