The number of geometrical isomers of [CrCl2en(NH3)2] are:
[en-ethylenediamine]
1. | 2 | 2. | 3 |
3. | 4 | 4. | 1 |
The geometry and the number of the unpaired electron(s) of \([MnBr_{4}]^{2-}\), respectively, are:
1. | Tetrahedral and 1 | 2. | Square planar and 1 |
3. | Tetrahedral and 5 | 4. | Square planar and 5 |
2.335 g of compound X (empirical formal CoH12N4Cl3) upon treatment with excess AgNO3 solution produces 1.435 g of a white precipitate. The primary and secondary valences of cobalt in compound X, respectively are:
[Given Atomic mass: Co = 59, Cl = 35.5, Ag = 108]
1. | 3, 6 | 2. | 3, 4 |
3. | 2, 4 | 4. | 4, 3 |
The total number of geometrical isomers possible for an octahedral complex of are:
(M = transition metal; A, B and C are monodentate ligands)
1. | 3 | 2. | 4 |
3. | 5 | 4. | 6 |
1. NO3- acts as a monodentate ligand.
2. The Ce atom has a coordination number of 12.
3. The shape of the complex ion is an icosahedron.
4. The solution is used as an oxidizing agent.
The complex that can exhibit linkage isomerism is:
1. | [Co(NH3)5H2O]Cl3 | 2. | [Co(NH3)5(NO2)]Cl2 |
3. | [Co(NH3)5NO3](NO3)2 | 4. | [CO(NH3)5Cl]SO4 |
Spin-only magnetic moments of [Fe(NH3)6]3+ and [FeF6]3- in BM are, respectively :
1. | 1.73 and 1.73 | 2. | 5.92 and 1.73 |
3. | 1.73 and 5.92 | 4. | 5.92 and 5.92 |
A metal ion has configuration. In octahedral complex entity of low spin, the number of electrons present in set of orbitals will be
1. | 6 | 2. | 4 |
3. | 0 | 4. | 2 |
The hybridizations of [Ni(CO)4] and [Cr(H2O)6]3+, respectively, are :
1. sp3 and d3sp2
2. dsp2 and d2sp3
3. sp3 and d2sp3
4. dsp2 and sp3d2
According to Crystal Field Theory (CFT), the compound, among the following, that forms a colored complex is:
1. [Ti(H2O)6]4+
2. [Cr(NH3)6]3+
3. K[V(F)6]
4. (NH4)2[TiCl6]