The bleaching action of SO2 is due to its
1. Acidic property
2. Basic property
3. Reducing property
4. Oxidising property
The physical property of hydrides of group 16 that decreases down the group is:
1. | Melting point | 2. | Thermal stability |
3. | Boiling point | 4. | Critical temperature |
The false statement regarding hydrides from the 15th group is:
1. | NH3 > PH3 > AsH3 > SbH3 > BiH3 | Thermal stability |
2. | N-H > P-H > As-H > Sb-H > Bi-H | E-H bond dissociation enthalpy |
3. | NH3 > PH3 > AsH3 > SbH3 > BiH3 | Reducing character |
4. | NH3 > PH3 > AsH3 > SbH3 > BiH3 | Basicity |
Among the following reactions, N2 is not generated by heating:
1. (NH4)2Cr2O7
2. NH4Cl + NaNO2
3. NH4Cl + CaO
4. Ba(N3)2
A brown-coloured mixture of two gases is obtained by reducing 6 N nitric acid with metallic copper. This mixture on cooling condenses to a blue liquid which on freezing (-30 oC) gives a blue solid. The correct statement for the blue liquid or solid is:
1. | It is referred to as the anhydride of nitrous acid. |
2. | It is an acidic oxide. Hence, it dissolves in alkalies producing nitrites. |
3. | It can also be prepared by the action of 50 % HNO3 on arsenious oxide and then cooling to 250 K. |
4. | All of the above. |
Which of the following statements is false?
1. | H3PO2, H3PO3 and H3PO4 all are tribasic and reducing in nature. |
2. | \(NO_{3}^{-}\), \(SO_{3}^{2-}\), \(CO_{3}^{2-}\), and \(BO_{3}^{3-}\), only \(SO_{3}^{2-}\) have pπ-dπ bonding . | Amongst anions
3. | \(SO_{3}^{2-}\), \(SO_{4}^{2-}\), \(S_{2}O_{4}^{2-}\) and \(HSO_{4}^{-}\), \(SO_{3}^{2-}\) is basic and reducing in nature. | Amongst anions
4. | Number of lone pair(s) of electrons on Xe atoms in XeF2, XeF4 and XeF6 are 3, 2 and 1 respectively._ |
Column-I | Column-II | ||
(A) | XX’ | (i) | T-shape |
(B) | XX’3 | (ii) | Pentagonal bipyramidal |
(C) | XX’5 | (iii) | Linear |
(D) | XX’7 | (iv) | Square Pyramidal |
(A) | (B) | (C) | (D) | |
1. | (iii) | (i) | (iv) | (ii) |
2. | (i) | (iv) | (iii) | (ii) |
3. | (iv) | (iii) | (ii) | (i) |
4. | (iii) | (iv) | (i) | (ii) |
The strong reducing behaviour of H3PO2 is due to:
1. Presence of one -OH group and two P-H bonds.
2. High electron gain enthalpy of phosphorus.
3. High oxidation state of phosphorus.
4. Presence of two -OH groups and one P-H bond.
The acidity of diprotic acids in aqueous solution increases in the order:
1. H2S < H2Se < H2Te
2. H2Se < H2S < H2Te
3. H2Te < H2S < H2Se
4. H2Se < H2Te < H2S
Match the name of process given in Column I with the name of compound given in Column II and mark the correct option.
Column I | Column II | ||
(a) | Pure nitrogen | (i) | Chlorine |
(b) | Haber process | (ii) | Sulphuric acid |
(c) | Contact process | (iii) | Ammonia |
(d) | Deacon's process | (iv) | Sodium azide or Barium azide |
(a) | (b) | (c) | (d) | |
1. | (iv) | (iii) | (ii) | (i) |
2. | (i) | (ii) | (iii) | (iv) |
3. | (ii) | (iv) | (i) | (iii) |
4. | (iii) | (iv) | (ii) | (i) |