Consider the following cell reaction
2Fe(s) + (g) + 4(aq) 2(aq) + 2(l)
E° = 1.67 V, At [] = 10 M, = 0.1 atm and pH = 3, the cell potential at 25 °C is :
1. 1.27 V
2. 1.77 V
3. 1.87 V
4. 1.57 V
Consider the change in the oxidation state of Bromine corresponding to different emf values as shown in the diagram below:
\(\small{BrO_4^-\ \overset{1.82V}{\longrightarrow}\ BrO_3^-\ \overset{1.5V}{\longrightarrow} HBrO\ \overset{1.595V}{\longrightarrow}\ Br_2 \overset{1.0652V}{\longrightarrow}\ Br^-}\)
Then the species undergoing disproportionation is:-
1.
2.
3.
4. HBrO
On electrolysis of dilute sulphuric acid using Platinum (Pt) electrode, the product obtained at the anode will be:
1. Oxygen gas
2. gas
3. gas
4. Hydrogen gas
The electrode potential of Cu electrode dipped in 0.025 M CuSO4 solution at 298 K is:
(standard reduction potential of Cu = 0.34 V)
1. 0.047 V
2. 0.293 V
3. 0.35 V
4. 0.387 V
Molten sodium chloride conducts electricity due to the presence of:
1. Free ions.
2. Free molecules.
3. Free electrons.
4. Atoms of sodium and chlorine.
Pairs of reactants (R) and product (P) are given below. The pair which can be used in a fuel cell is :
1.
2.
3.
4.
1. | pH of the solution will rise. | 2. | pH of the solution will fall. |
3. | No change in the pH of the solution. | 4. | None of the above. |
The metal that cannot be produced upon reduction of its oxide by aluminium is :
1. | K | 2. | Mn |
3. | Cr | 4. | Fe |
The unit of specific conductance is:
1. | ohm-1 cm-1 | 2. | ohm cm |
3. | ohm cm-1 | 4. | ohm-1 cm |
For the cell, Ti/Ti+(0.001M)||Cu2+(0.1M)|Cu, at
25 C is 0.83 V. Ecell can be increased :
1. By increasing [Cu2+]
2. By increasing [Ti+]
3. By decreasing [Cu2+]
4. None of the above.