To minimize the painful effects accompanying deep sea diving, oxygen diluted with less soluble helium gas is used as breathing gas by the divers. This is an example of the application of:
1. | Raoult's law | 2. | Henry's law |
3. | Ideal gas Equation | 4. | All of the above |
The graph representing Henry's law is given below:
The value of the slope will be
1. | \(4\times10^{-4}~\mathrm{torr}\) | 2. | \(5\times10^{-4}~\mathrm{torr}\) |
3. | \(4\times10^{4}~\mathrm{torr}\) | 4. | \(5\times10^{4}~\mathrm{torr}\) |
Henry’s law constant for the solution of methane in benzene at 298 K is 4.27 × 105 mm Hg. The mole fraction of methane in benzene at 298 K under 760 mm Hg will be:
1. 1.85 × 10–5
2. 192 × 10–4
3. 178 × 10–5
4. 18.7 × 10–5
The amount of benzoic acid (C6H5COOH) required for preparing 250 mL of 0.15 M solution in methanol is:
1. | 4.57 g | 2. | 3.57 g |
3. | 1.57 g | 4. | 12.57 g |
A 500 g toothpaste sample has 0.4 g fluoride concentration. The fluoride concentration in terms of ppm will be -
1. | 200 ppm | 2. | 400 ppm |
3. | 500 ppm | 4. | 800 ppm |
The partial pressure of ethane over a solution containing 6.56 × 10–2 g of ethane is 1 bar. If the solution contains 5.00 × 10–2 g of ethane, the partial pressure of the gas will be:
1. 0.66 bar
2. 0.96 bar
3. 0.76 bar
4. 0.19 bar
A solution of glucose (M.W = 180 g mol–1) in water is 10 % w/w. The mole fraction of each component in the solution is:
1. | Mole fraction of glucose - 0.44; mole fraction of water - 0.56 |
2. | Mole fraction of glucose - 0.056; mole fraction of water - 0.944 |
3. | Mole fraction of glucose - 0.011; mole fraction of water - 0.99 |
4. | Mole fraction of glucose - 0.36; mole fraction of water - 0.64 |
The solubility of H2S in water at STP is 0.195 m. The value of Henry's constant is-
1. | 274 atm | 2. | 285 atm |
3. | 295 atm | 4. | 278 atm |