The correct IUPAC name, among the following, is:
1. | Prop-3-yn-1-ol | 2. | But-4-ol-4-yne |
3. | But-3-ol-2-yne | 4. | But-3-yn-1-ol |
An organic compound contains 69% carbon, and 4.8% hydrogen, the remainder being oxygen. The masses of carbon dioxide, and water produced when 0.20 g of this substance is subjected to complete combustion would be respectively -
1. 0.506 g, 0.0864 g
2. 0.906 g, 0.0864 g
3. 0.0506 g, 0.864 g
4. 0.0864 g, 0.506 g
In the organic compound, the pair of hydridized orbitals involved in the formation of C2 – C3 bond is-
1. sp –
2. sp –
3. –
4. –
Any type of chromatography shares which of the following characteristic?
1. Use of molecules that are soluble in water.
2. Use of inert carrier gas.
3. Calculation of Rf value for the molecule separated.
4. Use of a mobile and a stationary phase.
The number of σ and π bonds in the molecule are -
1. | 6 C – C sigma ( σ C - C ) bonds, 5 C–H sigma ( ( σ C - H ) bonds, and 3 C=C pi ( π C - C ) |
2. | 6 C – C sigma ( σ C - C ) bonds, 5 C–H sigma ( ( σ C - H ) bonds, and 2 C=C pi ( π C - C ) |
3. | 6 C – C sigma ( σ C - C ) bonds, 6 C–H sigma ( ( σ C - H ) bonds, and 3 C=C pi ( π C - C ) |
4. | 6 C – C sigma ( σ C - C ) bonds, 6 C–H sigma ( ( σ C - H ) bonds, and 2 C=C pi ( π C - C ) |
The number of σ and π bonds in the molecule are:
1. 7 = ( , 11 = , and 0= π
2. 6 = ( , 12 = , and 0= π
3. 12 = ( , 6 = , and 1= π
4. 5 = ( , 13 = , and 1= π
The number of σ and π bonds in the molecule are -
1. 2 = ( , 1= , and 1= π
2. 2 = ( , 2= , and 0= π
3. 2 = ( , 1= , and 1= π
4. 2 = ( , 1= , and 1= π
Chlorine atom can be classified as:
1. | Carbocation | 2. | Nucleophile |
3. | Electrophile | 4. | Carbanion |
The correct hybridization states of carbon atoms in the above compound are -
1. | C1= sp , C2= sp3 | 2. | C1= sp2 , C2= sp |
3. | C1= sp3 , C2= sp | 4. | C1= sp , C2= sp2 |
The correct hybridization states of carbon atoms marked as 1,2,3 in the following compound are -
1. | C1= sp , C2= sp3 , C3= sp2 | 2. | C1= sp2 , C2= sp3 , C3= sp3 |
3. | C1= sp3 , C2= sp2 , C3= sp2 | 4. | C1= sp3 , C2= sp3 , C3= sp3 |