From the following, identify the reaction having the top position in the EMF series (standard reduction potential) according to their electrode potential at 298 K.
1. Mg2++ 2e–Mg(s)
2. Fe2+ + 2e– Fe(s)
3. Au3++ 3e–Au(s)
4. K++ le –K(s)
Standard reduction potentials of the half-reactions are given below:
The strongest oxidizing and reducing agents, respectively, are:
1. and
2. and
3. and
4. and
A solution contains Fe2+, Fe3+ and I– ions. This solution was treated with iodine at 35°C. E° for Fe3+/Fe2+ is +0.77 V and E° for I2/2I– = 0.536 V.
The favourable redox reaction is:
1. Fe2+ will be oxidized to Fe3+.
2. I2 will be reduced to I–.
3. There will be no redox reaction.
4. I– will be oxidized to I2.
Among the following hydrohalic compounds, the best reductant is -
The compound AgF2 (unstable) acts as a/ an:
1. Oxidising agent.
2. Reducing agent.
3. Both oxidising and reducing agent.
4. Neither oxidising and reducing agent.
Fluorine reacts with ice as per the following reaction
H2O(s) + F2(g) → HF(g) + HOF(g)
This reaction is a redox reaction because-
1. | F2 is getting oxidized. | 2. | F2 is getting reduced. |
3. | Both (1) and (2)
|
4. | None of the above. |
The oxidation number of sulphur and nitrogen in H2SO5 and NO3- are respectively-
1. | +6, +5 | 2. | -6, -6 |
3. | +8, +6 | 4. | -8, -6 |
The formulas for the following compounds are:
(a) Mercury(II) chloride and (b) Thallium(I) sulphate
1. HgCl2, Tl2SO4
2. Hg2Cl2, Tl2SO4
3. HgCl2, TlSO4
4. HgCl2, Tl3SO4
The correct statement(s) about the given reaction is -
\(\mathrm{{X} eO_{6 (aq)}^{4 -} + 2 F^{- 1}_{(aq)} + 6 H^{+}_{(aq )} \rightarrow}~\mathrm{{X} eO_{3 (g)} + {F}_{2 (g)} + 3 H_{2} O_{(l)}}\)
1. oxidises F-
2. The oxidation number of F increases from -1 to zero
3. is a stronger oxidizing agent that
4. All of the above.
The oxidising agent and reducing agent in the given reaction are
1. Oxidising agent = ; Reducing agent =
2. Oxidising agent = ; Reducing agent =
3. Oxidising agent = ; Reducing agent =
4. None of the above