Amongst the one with the highest boiling point is:
1. H2O because of H-bonding.
2. H2Te because of higher molecular weight.
3. H2S because of H-bonding.
4. H2Se because of lower molecular weight.
The strongest hydrogen bond present among the following is-
1.
2.
3.
4.
Compound that does not exhibit hydrogen bonding is-
1. | CH3CH2OH | 2. | |
3. | 4. |
Which of the following molecules exhibits H-bonding?
1. | CH4 | 2. | H2Se |
3. | N2H4 | 4. | H2S |
The type of molecular forces of attraction present in the following compound is:
1. | Intermolecular H-bonding. | 2. | Intramolecular H-bonding. |
3. | Van der Waal's force. | 4. | All of the above. |
Which molecule is least likely to form hydrogen bonds?
1. | \(\mathrm{NH}_3\) | 2. | \(\mathrm{H_2NOH}\) |
3. | \(\mathrm{HF}\) | 4. | \(\mathrm{CH_3F}\) |
The correct order of the boiling points of \(\mathrm{H}_2 \mathrm{O}, \mathrm{HF}, \text{ and} \ \mathrm{NH}_3\) is:
1. HF > H2O > NH3
2. H2O > HF > NH3
3. NH3 > HF > H2O
4. NH3 > H2O > HF
The incorrect order of boiling point is-
1.
2.
3.
4.
In which of the following compounds is an intramolecular hydrogen bond present?
1. | H2O2 | 2. | HCN |
3. | Cellulose | 4. | Concentrated acetic acid |
The correct order of H-bond strength in the following compounds is:
1. H2O > H2O2 > HF > H2S
2. HF > H2O2 > H2O > H2S
3. HF > H2O > H2S > H2O2
4. HF > H2O > H2O2 > H2S