Match the coordination number and type of hybridization with the distribution of hybrid orbitals in space based on Valence bond theory.

	Coordination number and type of hybridisation		Distribution of hybrid orbitals in space
(a)	4, sp3	(i)	Trigonal bipyramidal
(b)	4, dsp2	(ii)	Octahedral
(c)	5, sp3d	(iii)	Tetrahedral
(d)	6, d2sp3	(iv)	Square planar

 

	(a)	(b)	(c)	(d)
1.	(ii)	(iii)	(iv)	(i)
2.	(iii)	(iv)	(i)	(ii)
3.	(iv)	(i)	(ii)	(iii)
4.	(iii)	(i)	(iv)	(ii)

The potential energy (y) curve for H₂ formation as a function of internuclear distance (x) of the H atoms is shown below.

The bond energy of H₂ is:

Consider the given compound:


In the given options, the following for the above compound are, respectively:
(i) sp² hybridised carbon atoms
(ii) $\mathrm{\pi }$ bonds 

Match the compounds of Xe in Column I with the molecular structure in Column II.

Which of the compounds given below will exhibit a linear structure?

BF₃ is a planar and an electron deficient compound. Hybridization and number of electrons around the central atom, respectively are: 

Match List-I with List-II

Choose the correct answer from the options given below:

Which pair of ions among the following list do not constitute an iso-electronic pair?

1. Mn²⁺, Fe³⁺

2. Fe²⁺, Mn²⁺

3. O^2–, F^–

4. Na⁺, Mg²⁺

Which molecule among the following is non-polar?