Amongst the one with the highest boiling point is:
1. H2O because of H-bonding.
2. H2Te because of higher molecular weight.
3. H2S because of H-bonding.
4. H2Se because of lower molecular weight.
The correct order of electronegativity of hybrid orbitals of carbon is:
1. sp > sp2 < sp3
2. sp > sp2 > sp3
3. sp < sp2 > sp3
4. sp < sp2 < sp3
has a net dipole moment while
\(BeF_2\) has zero dipole moment because :
1. F is more electronegative than oxygen.
2. Be is more electronegative than oxygen.
3. molecule is linear and \(BeF_2\) is bent.
4. molecule is linear and is bent.
Match the compounds given in Column I with the hybridization and shape given in Column II and mark the correct option.
Column I | Column II |
A. XeF6 | 1. Distorted octahedral |
B. XeO3 | 2. Square planar |
C. XeOF4 | 3. Pyramidal |
D. XeF4 | 4. Square pyramidal |
A | B | C | D | |
1. | 1 | 2 | 4 | 3 |
2. | 4 | 3 | 1 | 2 |
3. | 4 | 1 | 2 | 3 |
4. | 1 | 3 | 4 | 2 |
Which of the following pairs of ions are isoelectronic and isostructural?
1.
2.
3.
4.
The correct order of \(\mathrm{C-O}\) bond length among \(\mathrm{CO},\mathrm{CO}_3^{2-},\) and \(\mathrm{CO_2}\) is :
1. \(\mathrm{CO}_2<\mathrm{CO}_3^{2-}<\mathrm{CO} \)
2. \(\mathrm{CO}<\mathrm{CO}_3^{2-}<\mathrm{CO}_2 \)
3. \(\mathrm{CO}_3^{2-}<\mathrm{CO}_2<\mathrm{CO} \)
4. \(\mathrm{CO}<\mathrm{CO}_2<\mathrm{CO}_3^{2-}\)
Mg2C3 reacts with water forming propyne . The number of sigma and pie bonds in \(C_{3}^{4-}\)is-
1. Two sigma and two pi bonds.
2. Three sigma and one pi bonds.
3. Two sigma and one pi bonds.
4. Two sigma and three pi bonds.
A pair in which both species are not likely to exist is:
1. | \(H^+_2,He^{2-}_2\) | 2. | \(H^-_2,He^{2+}_2\) |
3. | \(H^{2+}_2,He_2\) | 4. | \(H^+_2,He^{2+}_2\) |
Combination of atoms A and B that forms an anti-bonding molecular orbital is :
1.
2.
3.
4.
The correct order of increasing dipole moment is :
1. < < <
2. < < <
3. < < <
4. < < <