The geometry and the dipole moment of is:
1. | Angular (distorted tetrahedral) and non-zero. | 2. | Angular and zero. |
3. | Linear and zero. | 4. | Linear and non-zero. |
Which of the following atomic orbitals would have the greatest overlap to form the strongest covalent bond?
1. | 2s-2s (σ) | 2. | 2s-2p (σ) |
3. | 2p-2p (π) | 4. | 2p-2p (σ) |
The 'S' atom among the following that does not have \(\mathrm{sp}^3\) hybridization is
1. | \(\mathrm{SO}^{2-}_4\) | 2. | \(\mathrm{SF}_4\) |
3. | \(\mathrm{SF}_2\) | 4. | \(\mathrm{S}_8\) |
A bent T-shape molecule among the following is:
1. \(\mathrm{ICl}^-_4\)
2. \(\mathrm{PCl}_3\)
3. \(\mathrm{BrF}_3\)
4. \(\mathrm{I}^-_3\)
Which of the following species deviates from the octet rule?
1.
2.
3.
4.
A pair in which both species are not likely to exist is:
1. | \(H^+_2,He^{2-}_2\) | 2. | \(H^-_2,He^{2+}_2\) |
3. | \(H^{2+}_2,He_2\) | 4. | \(H^+_2,He^{2+}_2\) |
A molecule that has an unequal bond length is :
1. | ClF3 | 2. | BF3 |
3. | AlF3 | 4. | NF3 |
Amongst the one with the highest boiling point is:
1. H2O because of H-bonding.
2. H2Te because of higher molecular weight.
3. H2S because of H-bonding.
4. H2Se because of lower molecular weight.
The correct order of electronegativity of hybrid orbitals of carbon is:
1. sp > sp2 < sp3
2. sp > sp2 > sp3
3. sp < sp2 > sp3
4. sp < sp2 < sp3