Statement I: | The Balmer spectral line for H atom with lowest energy is located at \(\dfrac 5{36}\mathrm{ R_H~ cm^{-1}}\) (\(\mathrm{R_H}\) = Rydberg constant) |
Statement II: | When the temperature of blackbody increases, the maxima of the curve (intensity versus wavelength) shifts to shorter wavelength. |
Calculate the energy in corresponding to light of wavelength 45 nm:
(Planck's constant h = 6.63 × 10–34 Js: speed of light c = 3 × 108 ms–1)
1. 6.67 x 1015 J
2. 6.67 x 1011 J
3. 4.42 x 10-15 J
4. 4.42 x 10-18 J
The value of Planck's constant is 6.63 × 10–34 J s. The velocity of light is 3.0 × 108 m s–1. The closest value to the wavelength in nanometers of a quantum of light with a frequency of is:
1.
2.
3.
4.
If the energy value is E = 3.03 × 10–19 Joules, (h = 6.6×10–34 J x sec., C = 3×108 m/sec), then the value of the corresponding wavelength is:
1. | 65.3 nm | 2. | 6.53 nm |
3. | 3.4 nm | 4. | 653 nm |