In Rutherford's experiment, generally, the thin foil of heavy atoms like gold, platinum, etc. have been used to be bombarded by the α-particles.
If the thin foil of light atoms like aluminum etc. is used in Rutherford’s experiment, the difference that would be observed from the above results is :
1. The same results will be observed.
2. More deflection would be observed.
3. There will not be enough deflection.
4. None of the above.
Symbols and can be written,
whereas symbols and are not acceptable because:
1. | The general convention for representing an element along with its atomic number (A) and atomic mass (Z) is |
2. | The general convention for representing an element along with its atomic mass (A) and atomic number (Z) is |
3. | The general convention for representing an element along with its wavelength (A) and frequency (Z) is |
4. | The general convention for representing an element along with its isotopes (A) and atomic number (Z) is |
The correct arrangement of the following electromagnetic spectrum in the increasing order of frequency is:
1. | Cosmic rays < Amber light < Radiation of FM radio < X-rays < Radiation from microwave ovens |
2. | Radiation from FM radio < Radiation from microwave oven < Amber light < X- rays < Cosmic rays |
3. | Radiation from microwave ovens < Amber light < Radiation of FM radio < X-rays < Cosmic rays |
4. | Cosmic rays < X-rays < Radiation from microwave ovens < Amber light < Radiation of FM radio |
The work function for the Cesium atom is \(1.9~\mathrm{eV}.\) The threshold frequency of the radiation is:
1. | \(4.59 \times10^{14}~s^{-1}\) | 2. | \(8.59 \times10^{14}~s^{-1}\) |
3. | \(5.59 \times10^{-14}~s^{-1}\) | 4. | \(65.9 \times10^{14}~s^{-1}\) |
1. 32.22 × 10–16 J
2. 12.22 × 10–16 J
3. 22.27 × 10–16 J
4. 31.22 × 10–16 J
If the position of the electron were measured with an accuracy of +0.002 nm, the uncertainty in the momentum of the electron would be:
1. 5.637 × 10–23 kg m s–1
2. 4.637 × 10–23 kg m s–1
3. 2.637 × 10–23 kg m s–1
4. 3.637 × 10–23 kg m s–1
1. 2p and 3p
2. 4p
3. 2p
4. 3p
The unpaired electrons in Al and Si are present in the 3p orbital. The electrons that will experience a more effective nuclear charge from the nucleus are :
1. Electrons in the 3p orbital of silicon
2. Electrons in the 5d orbital of aluminium
3. Electrons in the 3p orbital of aluminium
4. Electrons in the 5p orbital of silicon
Identify the element with the highest number of unpaired electrons in its ground state from the given options :
1. | P
|
2. | Fe
|
3. | Kr
|
4. | Cr |
The number of electrons that can be present in the subshells having ms value of \(-\frac{1}{2}\) for n = 4 are:
1. 36
2. 4
3. 16
4. 2