A solution is prepared by adding 2 g of substance A to 18 g of water. The mass percent of the solute is:
1. 20%
2. 10%
3. 15%
4. 18%
The NaNO3 weighed out to make 50 mL of an aqueous solution containing 70.0 mg Na+ per ml is:
(Rounded off to the nearest integer) [Given: Atomic weight in g mol–1 – Na: 23; N: 14; O: 16]
1. 13 g
2. 26 g
3. 18 g
4. 22 g
An aqueous solution of urea containing 18 g of urea in 1500 cm3 of the solution has a density of 1.052 g/cm3. If the molecular weight of urea is 60, then the molality of the solution is-
1. 0.2
2. 0.192
3. 0.064
4. 1.2
When 50.0 kg of nitrogen gas (N2) and 10.0 kg of hydrogen gas (H2) are combined, what is the quantity of ammonia gas (NH3) produced?
1. 33.0 ×103 mol
2. 56.1×103 g
3. 6.5 ×103 g
4. None of the above
List I | List II | ||
a. | Micro | i. | m |
b. | Mega | ii. | m |
c. | Giga | iii. | m |
d. | Femto | iv. | m |
a | b | c | d | |
1. | i | iv | iii | ii |
2. | iii | iv | ii | i |
3. | ii | iii | iv | i |
4. | i | iii | iv | ii |
Sulphuric acid reacts with sodium hydroxide as follows
When 1L of 0.1 M sulphuric acid solution is allowed to react with 1 L of 0.1 M sodium hydroxide solution, the amount of sodium sulphate formed and its molarity in the solution obtained are respectively-
1. 0.1 M, 7.10 g
2. 7.10 g, 0.025 M
3. 0.025 M, 3.55 g
4. 3.55 g, 0.25 M
One mole of oxygen gas at STP is equal to:
(a) | 6 .022× 1023 molecules of oxygen |
(b) | 6.022 × 1023 atoms of oxygen |
(c) | 16 g of oxygen molecule |
(d) | 32 g of oxygen |
Choose the correct answer from the option given below:
1. | (a) and (b) | 2. | (a) and (c) |
3. | (a) and (d) | 4. | (c) and (d) |
The mass of CaCO3 required to react completely with 25 mL of 0.75 M HCl according to the given reaction would be:
CaCO3(s) + HCl(aq) ➡ CaCl2(aq) + CO2(g) + H2O(l)
1. 0.36 g
2. 0.09 g
3. 0.96 g
4. 0.66 g
The number of significant figures in the following numbers is:
(I). | 161 cm |
(II). | 0.0161 |
(III). | 1.61 |
1. 3, 3, 3
2. 3, 4, 3
3. 3, 2, 3
4. 3, 4, 4
Percentage of C, H & N of a compound is given as follows:
C=40%, H=13.33%, N=46.67%
The empirical formula of the compound will be:
1.
2.
3.
4.