Two pith balls carrying equal charges are suspended from a common point by strings of equal length, the equilibrium separation between them is \(r\) (as shown in Fig. I). Now, as shown in Fig. II, the strings are rigidly clamped at half the height. The equilibrium separation between the balls now becomes:
     
1. \(\frac{r}{\sqrt[3]{2}}\)
2. \(\frac{r}{\sqrt[2]{2}}\)
3. \(\frac{2r}{3}\)
4. none of the above

Subtopic:  Coulomb's Law |
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AIPMT - 2013
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The ratio of the magnitude of electric force to the magnitude of gravitational force for an electron and a proton will be:
(\(m_p=1.67\times10^{-27}~\text{kg}\)\(m_e=9.11\times10^{-31}~\text{kg}\))
1. \(2.4\times10^{39}\)
2. \(2.6\times10^{36}\)
3. \(1.4\times10^{36}\)
4. \(1.6\times10^{39}\)

Subtopic:  Coulomb's Law |
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A charge \(q\) is placed at the centre of the line joining two equal positive charges \(Q.\) The system of the three charges will be in equilibrium, if \(q\) is equal to:
1. \(\dfrac{-Q}{4}\) 2. \(\dfrac{Q}{4}\)
3. \(\dfrac{-Q}{2}\) 4. \(\dfrac{Q}{2}\)
 
Subtopic:  Coulomb's Law |
 68%
From NCERT
NEET - 2013
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Consider three charges \(q_1,~q_2,~q_3\) each equal to \(q\) at the vertices of an equilateral triangle of side \(l.\) What is the force on a charge \(Q\) (with the same sign as \(q\)) placed at the centroid of the triangle, as shown in the figure?

     

1. \(\dfrac{3}{4\pi \epsilon _{0}} \dfrac{Qq}{l^2}\) 2. \(\dfrac{9}{4\pi \epsilon _{0}} \dfrac{Qq}{l^2}\)
3. zero 4. \(\dfrac{6}{4\pi \epsilon _{0}} \dfrac{Qq}{l^2}\)
Subtopic:  Coulomb's Law |
 87%
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Consider the charges \(q,~q,\) and \(-q\) placed at the vertices of an equilateral triangle, as shown in the figure. Then the sum of the forces on the three charges is:

    

1. \(\frac{1}{4\pi \epsilon _{0}}\frac{q^{2}}{l^{2}}\)
2. zero
3. \(\frac{2}{4\pi \epsilon _{0}}\frac{q^{2}}{l^{2}}\)
4. \(\frac{3}{4\pi \epsilon _{0}}\frac{q^{2}}{l^{2}}\)

Subtopic:  Coulomb's Law |
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Two identical charged spheres suspended from a common point by two massless strings of lengths \(l,\) are initially at a distance \(d\) \(\left ( d\ll l \right )\) apart because of their mutual repulsion. The charges begin to leak from both the spheres at a constant rate. As a result, the spheres approach each other with a velocity \(v.\) Then, \(v\) varies as a function of the distance \(x\) between the sphere, as:
1. \(v\propto x\)
2. \(v\propto x^{-1/2}\)
3. \(v\propto x^{-1}\)
4. \(v\propto x^{1/2}\)
Subtopic:  Coulomb's Law |
 78%
From NCERT
NEET - 2016
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The accelerations of electron and proton due to the electrical force of their mutual attraction when they are 1 Å (=10-10 m) apart are respectively: (\(m_p=1.67\times10^{-27}~\text{kg},~m_e=9.11\times10^{-31}~\text{kg}\))

1. \(2.5\times10^{22}\) m/s2\(2.5\times10^{22}\) m/s2 
2. \(2.5\times10^{22}\) m/s2\(1.4\times10^{19}\) m/s2
3. \(1.4\times10^{19}\) m/s2\(2.5\times10^{22}\) m/s2
4. \(1.4\times10^{19}\) m/s2\(1.4\times10^{19}\) m/s2

Subtopic:  Coulomb's Law |
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