| 1. | \(1~\text{s}\) | 2. | \(2~\text{s}\) |
| 3. | \(3~\text{s}\) | 4. | \(4~\text{s}\) |
A pendulum is hung from the roof of a sufficiently high building and is moving freely to and fro like a simple harmonic oscillator. The acceleration of the bob of the pendulum is \(20\text{ m/s}^2\) at a distance of \(5\text{ m}\) from the mean position. The time period of oscillation is:
1. \(2\pi \text{ s}\)
2. \(\pi \text{ s}\)
3. \(2 \text{ s}\)
4. \(1 \text{ s}\)
A pendulum oscillates about its mean position \(\mathrm{C}.\) The position where the speed of the bob becomes maximum is: (ignore all dissipative forces)

| 1. | \(\mathrm{A}\) | 2. | \(\mathrm{B}\) |
| 3. | \(\mathrm{C}\) | 4. | \(\mathrm{D}\) |
| Assertion (A): | If a pendulum is suspended in a lift and the lift is falling freely, then its time period becomes infinite. |
| Reason (R): | The free-falling body has acceleration equal to the acceleration due to gravity. |
| 1. | Both (A) and (R) are True and (R) is the correct explanation of (A). |
| 2. | Both (A) and (R) are True but (R) is not the correct explanation of (A). |
| 3. | (A) is True but (R) is False. |
| 4. | Both (A) and (R) are False. |
A simple pendulum has a time period \(T\) in air. The bob is then completely immersed and continues to oscillate freely in a non-viscous liquid whose density is \(\left ( \dfrac{1}{16}\right )^\mathrm{th} \) of that of the bob. Assuming no damping and only the effect of buoyancy, what is the new time period of oscillation?
| 1. | \( 2 T \sqrt{\dfrac{1}{14}} \) | 2. | \( 2 T \sqrt{\dfrac{1}{10}} \) |
| 3. | \(4 T \sqrt{\dfrac{1}{15}} \) | 4. | \( 4 T \sqrt{\dfrac{1}{14}} \) |
| 1. | constant amplitude | 2. | decreasing amplitude |
| 3. | increasing amplitude | 4. | none of these |
| 1. | \(6\)\(\%\) |
| 2. | \(3\%\) |
| 3. | \(1.5\%\) |
| 4. | it will remain unchanged |