PCl5 is formed whereas NCl5 is not formed because:  
 
1.  Phosphorous has vacant d-orbitals while nitrogen does not have vacant d-orbitals. 
2. PCl5 is stable while NCl5 is unstable.
3.  Phosphorous is more reactive while nitrogen is inert. 
4. Phosphorous has a large size while nitrogen has a small size. 
 


Subtopic:  Group 15 - Preparation, Properties & Uses |
 93%
From NCERT
JEE
Please attempt this question first.
Hints
Please attempt this question first.

Consider the following reaction,

\(\begin{aligned} &\mathrm{PCl}_{5}+\mathrm{H}_{2} \mathrm{O} \longrightarrow \mathrm{A}+\mathrm{HCl} \\ &\mathrm{A}+\mathrm{H}_{2} \mathrm{O} \longrightarrow \mathrm{B}+\mathrm{HCl} \end{aligned}\)

then the maximum numbers of ionizable hydrogen in B are:

1. 2 
2. 0
3. 3
4. 1

Subtopic:  Group 16 - Preparation, Properties & Uses |
 58%
From NCERT
JEE
Please attempt this question first.
Hints
Please attempt this question first.

Lead nitrate decomposes on heating as:  

\(\mathrm{Pb}\left(\mathrm{NO}_{3}\right)_{2} \stackrel{\Delta}{\longrightarrow} \mathrm{A}+\mathrm{PbO}+\mathrm{O}_{2} \)

'A' on dimerization gives 'B', then the number of bridging oxygen atom(s) in 'B' is:

1. 1
2. 0
3. 2 
4. 3
Subtopic:  Group 15 - Preparation, Properties & Uses |
 69%
From NCERT
JEE
Please attempt this question first.
Hints
Please attempt this question first.

advertisementadvertisement

Statement-I:  E2O5 is less acidic than E2O3 (element E belongs to 15th group).
Statement-II:  E2O3 acidic strength decreases down the group (element E belongs to 15th group).
 
1.  Both Statement-I & Statement-II are true.
2.  Both Statement-I & Statement-II are false.
3.  Statement-I is true while Statement-II is false.
4.  Statement-I is false while Statement-II is true.
Subtopic:  Group 15 - Preparation, Properties & Uses |
 63%
From NCERT
JEE
Please attempt this question first.
Hints
Please attempt this question first.

How many of the following have N-N bonds N2O, N2O4, N2O3, N2O5

1. 1
1. 0
3. 3
4. 2
Subtopic:  Group 15 - Preparation, Properties & Uses |
 56%
From NCERT
JEE
Please attempt this question first.
Hints
Please attempt this question first.

The correct order of bond dissociation enthalpy of halogens is :

1. Cl2>F2>Br2>I2

2. I2>Br2>Cl2>F2

3. Cl2>Br2>F2>I2

4. F2>Cl2>Br2>I2

Subtopic:  Group 17 - Preparation, Properties & Uses |
 67%
From NCERT
JEE
Please attempt this question first.
Hints
Please attempt this question first.

advertisementadvertisement

Given below are two statements :

Statement I: α and β forms of sulphur can change reversibly between themselves with slow heating or slow cooling.
Statement II: At room temperature, the stable crystalline form of sulphur is monoclinic sulphur. 

1.  Statement I is false but Statement II is true.
2.  Both Statement I and Statement II are true.
3.  Statement I is true but Statement II is false.
4.  Both Statement I and Statement II are false.

Subtopic:  Group 16 - Preparation, Properties & Uses |
From NCERT
JEE
Please attempt this question first.
Hints
Please attempt this question first.

On heating compound (A) gives a gas (B) which is a constituent of air. This gas when treated with H2 in the presence of a catalyst gives another gas (C) which is basic in nature. (A) should not be-

1.  (NH4)2Cr2O7

2.  Pb(NO3)2

3.  NaN3

4.  NH4NO2

Subtopic:  Group 15 - Preparation, Properties & Uses |
 52%
From NCERT
JEE
Please attempt this question first.
Hints
Please attempt this question first.

Aqua regia is used for dissolving noble metals (Au, pt, etc.). The gas evolved in this process is: 

1. N2O5

2. N2O3 

3. N

4. NO 

Subtopic:  Group 17 - Preparation, Properties & Uses |
 71%
From NCERT
JEE
Please attempt this question first.
Hints
Please attempt this question first.

advertisementadvertisement

If the boiling point of H2O is 373 K, the boiling point of H2S will be:

1. Greater than 300 K but less than 373 K
2. Less than 300 K
3. More than 373 K
4. Equal to 373 K

Subtopic:  Group 16 - Preparation, Properties & Uses |
From NCERT
JEE
Please attempt this question first.
Hints
Please attempt this question first.