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Q. No.Pentahalides are more covalent than trihalides because-
1. Metal with high charge has more polarizing power
2. Metal with high charge has less ionization energy
3. Metal with high charge has low electronegativity
4. None of the above
1. Metal with high charge has more polarizing power
2. Metal with high charge has less ionization energy
3. Metal with high charge has low electronegativity
4. None of the above
Subtopic: Group 15 - Preparation, Properties & Uses |
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The strongest reducing agent among the given hydrides of Group 15 elements is-
1. NH3
2. PH3
3. AsH3
4. BiH3
1. NH3
2. PH3
3. AsH3
4. BiH3
Subtopic: Group 15 - Preparation, Properties & Uses |
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N2 is less reactive at room temperature due to -
1. High polarising power
2. High bond dissociation energy
3. High ionic character
4. None of the above
1. High polarising power
2. High bond dissociation energy
3. High ionic character
4. None of the above
Subtopic: Group 15 - Preparation, Properties & Uses |
90%
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The condition(s) required to maximize the yield of ammonia in Haber process is/are-
| 1. | High pressure (200 atm) condition |
| 2. | High temperature of 700 K |
| 3. | Use of a catalyst such as iron oxide mixed with small amounts of K2O and Al2O3 |
| 4. | All of the above |
Subtopic: Group 15 - Preparation, Properties & Uses |
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Consider the following reaction,
Cu2+(aq) + NH3(aq) → X(aq)
The product X is-
1. \([Cu(NH_3)_4(H_2O)_{2}]^{2+}\)
2. \([Cu(NH_3)_2]^{2+}\)
3. \(Cu(NH_3)_{3}\)
4. \([Cu(NH_3)_4]^{2+}\)
Subtopic: Group 15 - Preparation, Properties & Uses |
67%
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Subtopic: Group 15 - Preparation, Properties & Uses |
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Given below are two statements:
| Assertion (A): | Bond angle in PH4+ is higher than that in PH3 |
| Reason (R): | Lone pair-bond pair repulsion is stronger in PH3 than bond pair-bond pair repulsion in PH4+ . |
| 1. | Both (A) and (R) are true and (R) is the correct explanation of (A). |
| 2. | Both (A) and (R) are true but (R) is not the correct explanation of (A). |
| 3. | (A) is true but (R) is false. |
| 4. | (A) is false but (R) is true. |
Subtopic: Group 15 - Preparation, Properties & Uses |
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When white phosphorus is heated with concentrated NaOH solution in an inert atmosphere of CO2 , the product(s) obtained is/are-
1. \( PH_3\)
2. \(NaH_2PO_2\)
3. P2O5
4. Both 1 and 2
1. \( PH_3\)
2. \(NaH_2PO_2\)
3. P2O5
4. Both 1 and 2
Subtopic: Group 15 - Preparation, Properties & Uses |
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Given below are two statements:
| Assertion (A): | When PCl5 is heated then PCl3 and Cl2 are obtained as products. |
| Reason (R): | PCl5 gives POCl3 with water. |
| 1. | Both (A) and (R) are true and (R) is the correct explanation of (A). |
| 2. | Both (A) and (R) are true but (R) is not the correct explanation of (A). |
| 3. | (A) is true but (R) is false. |
| 4. | (A) is false but (R) is true. |
Subtopic: Group 15 - Preparation, Properties & Uses |
78%
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Consider the following reaction:
PCl5 + H2O → A + 2HCl
The product A is :
1. H3PO2
2. H3PO4
3. POCl3
4. None of the above
Subtopic: Group 15 - Preparation, Properties & Uses |
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