When three identical bulbs are connected in series, the consumed power is \(10\) W. If they are now connected in parallel then the consumed power will be:
1. \(30\) W
2. \(90\) W
3. \(\frac{10}{3}\) W
4. \(270\) W

In a hot wire ammeter due to the flowing of the current, the temperature of the wire is increased by \(5^{\circ}\) C. If the value of the current is doubled, then the increase in temperature will be:
1. \(15^{\circ}\) C
2. \(20^{\circ}\) C
3. \(25^{\circ}\) C
4. \(30^{\circ}\) C

The current in \(8~\Omega\) resistance is (in the figure below):

1. \(0.69\) A
2. \(0.92\) A
3. \(1.30\) A
4. \(1.6\) A

If the power dissipated in \(5~\Omega\) is \(20\) W then the power dissipated in \(4~\Omega\) is:
   
1. \(4\) W
2. \(6\) W
3. \(10\) W 
4. \(20\) W

The terminal potential difference of a cell is greater than its emf when:

The net resistance of the circuit between \(A\) and \(B\) is:

A car battery of emf \(12~\text{V}\) and internal resistance \(5\times 10^{-2}~\Omega\) receives a current of \(60~\text{A}\) from an external source. The terminal voltage of the battery is:

If there are two bulbs of (\(40~\text{W},200~\text{V}\)), and (\(100~\text{W},200~\text{V}\)), then the correct relation for their resistance is:
1. \(R_{40}<R_{100}\)
2. \(R_{40}>R_{100}\)
3. \(R_{40}=R_{100}\)
4. no relation can be predicted

According to the Faraday Law of electrolysis, the mass deposited at electrode will be proportional to:

1. m ∝ I²

2. m ∝ Q

3. m ∝ Q²

4. 'm' does not depend on Q