- 1(current)
Q. No.Two batteries with emf \(12~\text{V}\) and \(13~\text{V}\) are connected in parallel across a load resistor of \(10~\Omega.\) The internal resistances of the two batteries are \(1~\Omega\) and \(2~\Omega\) respectively. The voltage across the load lies between:
1. \(11.6~\text{V}~\text{and}~11.7~\text{V}\)
2. \(11.5~\text{V}~\text{and}~11.6~\text{V}\)
3. \(11.4~\text{V}~\text{and}~11.5~\text{V}\)
4. \(11.7~\text{V}~\text{and}~11.8~\text{V}\)
Subtopic: Grouping of Cells |
From NCERT
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A cell \(E_1\) of emf \(6~\text{V}\) and internal resistance \(2~\Omega\) is connected with another cell \(E_2\) of emf \(4~\text{V}\) and internal resistance \(8~\Omega\) (as shown in the figure). The potential difference across points \(X\) and \(Y\) is:
1. \(10~\text{V}\)2. \(3.6~\text{V}\)
3. \(5.6~\text{V}\)
4. \(2~\text{V}\)
Subtopic: Grouping of Cells |
57%
JEE
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Two identical cells each of emf \(1.5\) V are connected in parallel across a parallel combination of two resistors each of resistance \(20~\Omega\). A voltmeter connected in the circuit measures \(1.2\) V. The internal resistance of each cell is:
1. \(2.5~\Omega\)
2. \(4~\Omega\)
3. \(5~\Omega\)
4. \(10~\Omega\)
1. \(2.5~\Omega\)
2. \(4~\Omega\)
3. \(5~\Omega\)
4. \(10~\Omega\)
Subtopic: Grouping of Cells |
From NCERT
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Two cells of the same emf but different internal resistances \(r_1\) and \(r_2\) are connected in series with a resistance \(R\). The value of resistance \(R\), for which the potential difference across the second cell is zero, is:
1. \(r_2-r_1\)
2. \(r_1-r_2\)
3. \(r_1\)
4. \(r_2\)
1. \(r_2-r_1\)
2. \(r_1-r_2\)
3. \(r_1\)
4. \(r_2\)
Subtopic: Grouping of Cells |
From NCERT
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The combination of two identical cells, whether connected in series or parallel combination provides the same current through an external resistance of \(2~\Omega\). The value of the internal resistance of each cell is:
1. \(2~\Omega\)
2. \(4~\Omega\)
3. \(6~\Omega\)
4. \(8~\Omega\)
1. \(2~\Omega\)
2. \(4~\Omega\)
3. \(6~\Omega\)
4. \(8~\Omega\)
Subtopic: Grouping of Cells |
From NCERT
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In the circuit shown in the figure, the internal resistances of \(5\) V and \(8\) V cells are \(3\) \(\Omega\) and 4 \(\Omega,\) respectively. The current (in amperes) flows through the 4 \(\Omega\) external resistor connected across points \(A\) and \(B\) is \(\dfrac{1}{n}~\text{A}.\)
The value of \(n =\)
1. \(5\)
2. \(15\)
3. \(10\)
4. \(7\)
The value of \(n =\)1. \(5\)
2. \(15\)
3. \(10\)
4. \(7\)
Subtopic: Grouping of Cells |
54%
From NCERT
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The current through a \(5~\Omega\) resistance remains the same, irrespective of its connection across a series or parallel combination of two identical cells. The internal resistance of the cell is:
1. \(5~\Omega\)
2. \(10~\Omega\)
3. \(15~\Omega\)
4. \(20~\Omega\)
1. \(5~\Omega\)
2. \(10~\Omega\)
3. \(15~\Omega\)
4. \(20~\Omega\)
Subtopic: Grouping of Cells |
78%
From NCERT
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- 1(current)
Q. No.
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