A block of mass \(m\) is placed on a surface with a vertical cross section given by \(y=\frac{x^3}{6}\). If the coefficient of friction is \(0.5\), then the maximum height above the ground at which the block can be placed without slipping is:
1. \( \frac{2}{3}~\text{m} \)
2. \( \frac{1}{3} ~\text{m} \)
3. \( \frac{1}{2} ~\text{m} \)
4. \( \frac{1}{6} ~\text{m}\)

Subtopic:  Friction |
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Given in the figure are two blocks \(A\) and \(B\) of weight \(20~\text{N}\) and \(100~\text{N}\), respectively. These are being pressed against a wall by a force \(F\) as shown. If the coefficient of friction between the blocks is \(0.1\) and between block \(B\) and the wall is \(0.15\), the frictional force applied by the wall on block \(B\) is:
       
1. \(100~\text{N}\)
2. \(80~\text{N}\)
3. \(120~\text{N}\)
4. \(150~\text{N}\)

Subtopic:  Friction |
From NCERT
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If a body moving in a circular path maintains a constant speed of \(10~\text{ms}^{–1},\) then which of the following correctly describes the relation between acceleration and radius?
1. 3.
2. 4.
Subtopic:  Uniform Circular Motion |
From NCERT
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A block of mass \({m} = 10~\text{kg}\) rests on a horizontal table. The coefficient of friction between the block and the table is \(0.05.\) When hit by a bullet of mass \(50~\text{g}\) moving with speed \(v\) that gets embedded in it, the block moves and comes to rest after moving a distance of \(2~\text m\) on the table. If a freely falling object were to acquire speed \(10 v\) after being dropped from a height \({H},\) then neglecting energy losses taking \({g}=10~\text{ms}^{-2},\) the value of \({H}\) is close to:
1. \(0.02~\text{km}\)
2. \(0.03~\text{km}\)
3. \(0.05~\text{km}\)
4. \(0.04~\text{km}\)
Subtopic:  Application of Laws |
From NCERT
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A conical pendulum of length \(1~\text{m}\) makes an angle \(\theta=45^\circ\) with respect to the \(z\text-\)axis and moves in a circle in the \(xy\) plane. The radius of the circle is \(0.4~\text{m}\) and its center is vertically below \(O.\) The speed of the pendulum, in its circular path, will be:
(Take \({g}=10~\text{ms}^{-2})\)
   
1. \(0.4~\text{m/s}\)
2. \(2~\text{m/s}\)
3. \(0.2~\text{m/s}\)
4. \(4~\text{m/s}\)
Subtopic:  Uniform Circular Motion |
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Two masses \(m_1=5~\text{kg}\) and \(m_2=10~\text{kg}\), connected by an inextensible string over a frictionless pulley, are moving as shown in the figure. The coefficient of friction of the horizontal surface is \(0.15\). The minimum weight \(m\) that should be put on top of \(m_2\) to stop the motion is:

                  

1. \(18.3~\text{kg}\)
2. \(23.3~\text{kg}\)
3. \(43.3~\text{kg}\)
4. \(10.3~\text{kg}\)

Subtopic:  Friction |
From NCERT
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A particle is moving with a uniform speed in a circular orbit of radius \(R\) in a central force inversely proportional to the \(n^{\text{th}}\) power of \(R\). If the period of rotation of the particle is \(T\), then:
1. \(T \propto R^{3 / 2} ~\text{for any } n\)
2. \(T \propto R^{\frac{{n}}{2}+1} \)
3. \({T} \propto {R}^{({n}+1) / 2} \)
4. \( T \propto R^{n / 2} \)

Subtopic:  Uniform Circular Motion |
From NCERT
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The mass of a hydrogen molecule is \(3.32 \times 10^{-27}~\text{kg}.\) If \(10^{23}\) hydrogen molecules strike, per second, a fixed wall of area \(2~\text{cm}^2\) at an angle of \(45^\circ\) to the normal, and rebound elastically with a speed of \(10^3~\text{m/s},\) then the pressure on the wall is nearly:
1. \( 2.35 \times 10^3 ~\text{N/m}^2 \)
2. \(4.70 \times 10^3 ~\text{N/m}^2 \)
3. \(2.35 \times 10^2 ~\text{N/m}^2 \)
4. \(4.70 \times 10^2 ~\text{N/m}^2 \)

Subtopic:  Newton's Laws |
From NCERT
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A given object takes \(n\) times more time to slide down a \(45^\circ\) rough inclined plane as it takes to slide down a perfectly smooth \(45°\) incline. The coefficient of kinetic friction between the object and the incline is:
1. \(\sqrt{1-\frac{1}{n^2}}\)
2. \(1-\frac{1}{n^2}\)
3. \(\frac{1}{2-n^2}\)
4. \(\sqrt {\frac{1}{1-n^2}}\)
Subtopic:  Friction |
From NCERT
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Two particles of the same mass \(m\) are moving in circular orbits because of force given by \(F(r) =\left( \frac{-16}{r}-r^3\right). \) The first particle is at a distance \(r = 1 \) and the second at \(r = 4. \) The best estimate for the ratio of kinetic energies of the first and the second particle is closest to:
1. \(3\times 10^-3\)
2. \(6\times 10^2\)
3. \(6\times 10^{-2}\)
4. \( 10^{-1}\)
Subtopic:  Uniform Circular Motion |
From NCERT
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