The graph between $\log \frac{\mathrm{x}}{\mathrm{m}}$ vs log p is given below:

What is the value of the slope?

1. ${\left(\frac{1}{2}\right)}^{\mathrm{n}}$

2. n

3. $\frac{1}{\mathrm{n}}$

4.$\frac{1}{{\left(\mathrm{n}\right)}^2}$

In the Freundlich adsorption isotherm, the value of 1/n is:
1. Between 0 and 1 in all cases.
2. Between 2 and 4 in all cases.
3. 1 in the case of physical adsorption.
4. 1 in the case of chemisorption.

An adsorption isotherm is a plot between:

The equation that represents a Freundlich adsorption isotherm is: 

1. $\frac{x}{m}=k{p}^{0.3}$

2. $\frac{x}{m}=k{p}^{2.5}$

3. $\frac{x}{m}=k{p}^{-0.5}$

4. $\frac{x}{m}=k{p}^{-1}$

The correct curve for Freundlich's adsorption isotherm is:

1.		2.
3.		4.

Consider the following graph between $\frac{\mathrm{x}}{\mathrm{m}}$ (extent of adsorption) and pressure:

What is the correct relation between T₁, T₂, and T₃? 

1. T₃ <  T₂  > T₁
2. T₁ < T₂  < T₃
3. T₁ > T₂  > T₃
4. None of the above

$\mathrm{}$

According to Freundlich adsorption isotherm, at high pressure, the value of $\frac{\mathrm{x}}{\mathrm{m}}$ is - 

1. Directly proportional to the pressure.

2. Inversely proportional to the pressure.

3. Directly proportional to the square of the pressure.

4. Independent of the pressure.

In an adsorption experiment, a graph between log(x/m) versus log P was found to be linear with a slope of 45$°$. The intercept on the y-axis was found to be 0.3. What will be the value of x/m at a pressure of 3 atm for the Freundlich adsorption isotherm when 1/n remains constant?

[Antilog 0.3 = 2]

1.  2

2.  4

3.  6

4.  5