The standard electrode potential for Sn4+/Sn2+ couple is +0.15 V and that for the Cr3+/Cr couple is -0.74 V. These two couples in their standard state are connected to make a cell. The cell potential will be: 

1. +0.89 V 2. +0.18 V
3. +1.83 V 4. +1.199 V
Subtopic:  Electrode & Electrode Potential |
 90%
From NCERT
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A button cell used in watches functions as following
Zn(s) + Ag2O(s) + H2O(l) \(\rightleftharpoons\) 2Ag(s) + Zn2+(aq) + 2OH(aq)
If half-cell potentials are-

Zn2+(aq) + 2e→ Zn(s)  Eo = – 0.76 V 
Ag2O(s) + H2O(l) + 2e → 2Ag(s) + 2OH(aq) Eo = 0.34 V

The cell potential will be:

1. 0.42 V 2. 0.84 V
3. 1.34 V 4. 1.10 V
Subtopic:  Electrode & Electrode Potential |
 87%
From NCERT
AIPMT - 2013
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Given the standard electrode potentials:

K+/K = –2.93 V
Ag+/Ag = 0.80 V
Hg2+/Hg = 0.79 V
Mg2+/Mg = –2.37 V
Cr3+/Cr = – 0.74 V
The correct increasing order of reducing power of the metals is:  
1. Cr < Mg < K < Ag < Hg 2. Mg < K < Ag < Hg < Cr
3. K < Ag < Hg < Cr < Mg 4. Ag < Hg < Cr < Mg < K
Subtopic:  Electrode & Electrode Potential |
 86%
From NCERT
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Molten sodium chloride conducts electricity due to the presence of: 

1. Free ions.

2. Free molecules.

3. Free electrons.

4. Atoms of sodium and chlorine.

Subtopic:  Electrode & Electrode Potential |
 80%
From NCERT
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The metal that cannot be produced upon reduction of its oxide by aluminium is :

1. K 2. Mn
3. Cr 4. Fe
Subtopic:  Electrode & Electrode Potential |
 73%
From NCERT
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The difference between the electrode potentials of two electrodes when no current is drawn through the cell is called:
1. Cell potential.
2. Cell emf.
3. Potential difference.
4. Cell voltage.

Subtopic:  Electrode & Electrode Potential |
 63%
From NCERT
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A gas X at 1 atm is bubbled through a solution containing a mixture of 1 M Yand 1 M Z- at 25 oC . If the reduction potential of Z > Y > X, then:

1. Y will oxidize X but not Z.  2. Y will oxidize Z but not X.
3. Y will oxidize both X and Z.  4. Y will reduce both X and Z.

Subtopic:  Electrode & Electrode Potential |
 69%
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If EFe2+/Feo = -0.441 V and  EFe3+/Fe2+o = 0.771 V, the standard emf of the reaction: 

Fe + 2Fe3+→ 3Fe2+ will be:

1. 0.330 V 2. 1.653 V
3. 1.212 V 4. 0.111 V
Subtopic:  Electrode & Electrode Potential |
 73%
From NCERT
AIPMT - 2006
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Consider the following relations for emf of an electrochemical cell:

(a) emf of cell = (Oxidation potential of anode) – (Reduction potential of cathode)
(b) emf of cell = (Oxidation potential of anode) + (Reduction potential of cathode)
(c) emf of cell = (Reduction potential of anode) + (Reduction potential of cathode)
(d) emf of cell = (Oxidation potential of anode) – (Oxidation potential of cathode)


Which of the following combinations correctly represents the relation for the emf of the cell?

1. (a) and (b) 2. (c) and (d)
3. (b) and (d) 4. (c) and (a)
Subtopic:  Electrode & Electrode Potential |
 69%
From NCERT
AIPMT - 2010
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The correct statement among the following options is: 

1. Ecell and ∆rG of cell reaction are both extensive properties.
2. Ecell and ∆rG of cell reaction are both intensive properties.
3. Ecell is an intensive property while ∆rG of cell reaction is an extensive property.
4. Ecell is an extensive property while ∆rG of cell reaction is an intensive property.

Subtopic:  Electrode & Electrode Potential |
 73%
From NCERT
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