The de-Broglie wavelength of an electron is the same as that of a photon of wavelength \(\lambda\). If the mass of an electron is \(m,\) then its kinetic energy will be:
1. \(\frac{h^{2} m}{2 \lambda^{2}}\) 2. \(\frac{2 h m^{2}}{\lambda^{2}}\)
3. \(\frac{h^{2} \lambda^{2}}{2 m}\) 4. \(\frac{h^{2}}{2 m \lambda^{2}}\)

Subtopic:  De-broglie Wavelength |
 80%
Level 1: 80%+
Hints
Links

The variation of the kinetic energy \((K)\) of photoelectrons as a function of the frequency \((f)\) of the incident radiation is best shown by:
1.   2.
3. 4.
Subtopic:  Einstein's Photoelectric Equation |
 74%
Level 2: 60%+
Hints
Links

On which surface is the electron beam made to fall in the Davisson-Germer experiment?

1. Iron crystals

2. Nickel crystals

3. Gold crystals

4. Cesium crystals

 65%
Level 2: 60%+
Hints
Links

advertisementadvertisement

The correct graph between the maximum energy of a photoelectron \(\left(K_{max}\right)\) and the inverse of the wavelength \(\left(\frac{1}{\lambda}\right)\) of the incident radiation is given by the curve:


   
1. \(A\) 2. \(B\)
3. \(C\) 4. None of these
Subtopic:  Einstein's Photoelectric Equation |
 82%
Level 1: 80%+
Hints
Links

If alpha, beta and gamma rays carry the same momentum, which has the longest wavelength?

1. Alpha rays 2. Beta rays
3. Gamma rays 4. None, all have same wavelength
Subtopic:  De-broglie Wavelength |
 70%
Level 2: 60%+
Hints
Links

The photoelectric effect is used by a photocell to convert:

1. Change in the frequency of light into a change in electric voltage.
2. Change in the intensity of illumination into a change in photoelectric current.
3. Change in the intensity of illumination into a change in the work function of the photocathode.
4. Change in the frequency of light into a change in the electric current.
Subtopic:  Photoelectric Effect: Experiment |
 66%
Level 2: 60%+
AIPMT - 2006
Hints
Links

advertisementadvertisement

A \(200~\text{W}\) sodium street lamp emits yellow light of wavelength \(0.6~\mu\text{m}\). If it is \(25\%\) efficient in converting electrical energy to light, how many photons of yellow light does it emit per second?
1. \(1.5\times 10^{20}\)
2. \(6\times 10^{18}\)
3. \(62\times 10^{20}\)
4. \(3\times 10^{19}\)

Subtopic:  Particle Nature of Light |
 74%
Level 2: 60%+
AIPMT - 2012
Hints
Links

In the photoelectric emission process from a metal of work function \(1.8\) eV, the kinetic energy of most energetic electrons is \(0.5\) eV. What is the corresponding stopping potential?
1. \(1.3\) V
2. \(0.5\) V
3. \(2.3\) V
4. \(1.8\) V
Subtopic:  Einstein's Photoelectric Equation |
 77%
Level 2: 60%+
AIPMT - 2011
Hints
Links

Electrons used in an electron microscope are accelerated by a voltage of \(25\) kV. If the voltage were increased to \(100\) kV, then the de-Broglie wavelength associated with the electrons would:
1. decrease by \(2\) times
2. decrease by \(4\) times
3. increase by \(4\) times
4. increase by \(2\) times
Subtopic:  De-broglie Wavelength |
 80%
Level 1: 80%+
AIPMT - 2011
Hints
Links

advertisementadvertisement

A source \(S_1\) is producing, \(10^{15}\) photons per sec of wavelength \(5000~\mathring{A}.\) Another source \(S_2\) is producing \(1.02\times 10^{15}\) photons per second of wavelength \(5100~\mathring{A}.\) Then the ratio of the power of \(S_2\) to the power of \(S_1\) is equal to:
1. \(1.00\) 2. \(1.02\)
3. \(1.04\) 4. \(0.98\)
Subtopic:  Particle Nature of Light |
 77%
Level 2: 60%+
AIPMT - 2010
Hints
Links