The correct Bernoulli's equation is (symbols have their usual meaning):
1. \(P+\rho g h+\dfrac{1}{2} \rho v^2=\text { constant }\)
2. \({P}+\rho {gh}+\rho {v}^2=\text{constant}\)
3. \(P+{mgh}+\dfrac{1}{2} {mv}^2=\text { constant }\)
4. \({P}+\dfrac{1}{2} \rho g h+\dfrac{1}{2} \rho {v}^2=\text { constant }\)
Subtopic:  Bernoulli's Theorem |
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A water tank, filled with water, has a small hole at a depth \(h\) from the top surface of the water. If the tank is open to the atmosphere and the cross-sectional area of the tank is much larger than that of the hole, then the speed of efflux is given by:
1. \(\sqrt{gh}\)
2. \(\sqrt{2gh}\)
3. \(2\sqrt{gh}\)
4. \(\sqrt{gh/2}\)
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An open-top tank, filled up to a height of \(5~\text m,\) has a hole at the bottom. What will be the velocity of water coming out of the hole?
(take \(g=10~\text{m/s}^2\) )
                     
1. \(100~\text {m/s}\)
2. \(50~\text {m/s}\)
3. \(10~\text {m/s}\)
4. \(8~\text {m/s}\)
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A cylinder of height \(20~\text{m}\) is completely filled with water. The velocity of efflux of water (in \(\text{ms}^{-1}\)) through a small hole on the side wall of the cylinder near its bottom, is: 
1. \(10~\text{m/s}\) 
2. \(20~\text{m/s}\)
3. \(25.5~\text{m/s}\)
4. \(5~\text{m/s}\) 

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The speed of water stream at which velocity head is \(10\text{ cm}\) of water will be: (take \(g = 1000\text{ cm/s}^2\))

1. \(121.2\text{ cm/s}\)

2. \(173.1\text{ cm/s}\)

3. \(141.4\text{ cm/s}\)

4. \(135.5\text{ cm/s}\)

Subtopic:  Bernoulli's Theorem |
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The inlet and outlet pipes have the same cross-section. At what speed \(v\) should water flow into the tank, so that the water level remains steady?
          
1. \(\sqrt{gH}\) 2. \(\sqrt{2gH}\)
3. \(\large\sqrt\frac{gH}{2}\) 4. \(2\sqrt{gH}\)
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The speed of flow past the lower surface of a wing of an aeroplane is \(50\text{ m/s}.\) What speed of flow over the upper surface will give a dynamic lift of \(1000\text{ Pa}~\)? (density of air = \(1.3\text{ kg/m}^3\)):

1. \(25.55\text{ m/s}\)

2. \(63.55\text{ m/s}\)

3. \(13.25\text{ m/s}\)

4. \(6.355\text{ m/s}\)

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Bernoulli's theorem is based on the conservation of:
1. momentum
2. mass
3. energy
4. angular momentum
Subtopic:  Bernoulli's Theorem |
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If water is flowing through a pipe located \(4~\text{m}\) above the ground, and the reference level is taken at the ground with \(g =10 ~\text{m/s}^2,\) what will be its potential energy per unit volume?
1. \(20~\text{kJ/m}^3\) 2. \(10~\text{kJ/m}^3\)
3. \(40~\text{kJ/m}^3\) 4. \(30~\text{kJ/m}^3\)
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Water flows through a pipe at a speed of \(2~\text{m/s}.\) The kinetic energy per unit volume of the flowing water is:
1. \(500~\text{J/m}^3\) 2. \(1000~\text{J/m}^3\)
3. \(1500~\text{J/m}^3\) 4. \(2000~\text{J/m}^3\)
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