Match List I with List II.
List I
(Spectral Lines of Hydrogen for transitions from)
List II
(Wavelength (nm))
\(\mathrm{A.}\) \(n_2=3\)  to \(n_1=2\)  \(\mathrm{I.}\) \(410.2\)
\(\mathrm{B.}\) \(n_2=4\)  to \(n_1=2\)  \(\mathrm{II.}\) \(434.1\)
\(\mathrm{C.}\) \(n_2=5\)  to \(n_1=2\)  \(\mathrm{III.}\) \(656.3\)
\(\mathrm{D.}\) \(n_2=6\) to \(n_1=2\)  \(\mathrm{IV.}\) \(486.1\)
 
Choose the correct answer from the options given below:
1. \(\mathrm{A - III, B - IV, C - II, D - I}\)
2. \(\mathrm{A - IV, B - III, C - I, D - II}\)
3. \(\mathrm{A - I, B - II, C - III, D - IV}\)
4. \(\mathrm{A - II, B - I, C - IV, D - III}\)
Subtopic:  Spectral Series |
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Given below are two statements:
Statement I: Atoms are electrically neutral as they contain equal number of positive and negative charges.
Statement II: Atoms of each element are stable and emit their characteristic spectrum.
 
In the light of the above statements, choose the most appropriate answer from the options given below:
1. Both Statement I and Statement II are incorrect.
2. Statement I is correct but Statement II is incorrect.
3. Statement I is incorrect but Statement II is correct.
4. Both Statement I and Statement II are correct.
Subtopic:  Spectral Series |
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Match List-I with List-II 
List-I
(Series)
List-II
(Wave number in cm–1)
A. Balmer series I. \( R\left(\dfrac{1}{1^2}-\dfrac{1}{n^2}\right) \)
B. Lyman series II. \( R\left(\dfrac{1}{4^2}-\dfrac{1}{n^2}\right) \)
C. Brackett series III. \( R\left(\dfrac{1}{5^2}-\dfrac{1}{n^2}\right) \)
D. Pfund series  IV. \( R\left(\dfrac{1}{2^2}-\dfrac{1}{n^2}\right)\)
 
Choose the correct answer from the options given below:
1. A-I, B-IV, C-III, D-II
2. A-II, B-III, C-IV, D-I
3. A-IV, B-I, C-II, D-III
4. A-III, B-II, C-I, D-IV
Subtopic:  Spectral Series |
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The spectral series which corresponds to the electronic transition from the levels \(\mathrm{n}_{2}=5,6,\ldots \) to the level \(\mathrm{n}_{1}=4\mathrm~\) is:
1. Pfund series
2. Brackett series
3. Lyman series
4. Balmer series
Subtopic:  Spectral Series |
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Some energy levels of a molecule are shown in the figure with their wavelengths of transitions. Then:
 
1. \(\lambda_{3}>\lambda_{2},\lambda_{1}=2\lambda_{2}\)
2. \(\lambda_{3}>\lambda_{2},\lambda_{1}=4\lambda_{2}\)
3. \(\lambda_{1}>\lambda_{2},\lambda_{2}=2\lambda_{3}\)
4. \(\lambda_{2}>\lambda_{1},\lambda_{2}=2\lambda_{3}\)
Subtopic:  Spectral Series |
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In hydrogen spectrum, the shortest wavelength in the Balmer series is \(\lambda\). The shortest wavelength in the Bracket series is:
1. \(16\lambda\)
2. \(2\lambda\)
3. \(4\lambda\)
4. \(9\lambda\)
Subtopic:  Spectral Series |
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The wavelength of Lyman series of hydrogen atom appears in:
1. visible region
2. far infrared region
3. ultraviolet region
4. infrared region
Subtopic:  Spectral Series |
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The ratio of wavelengths of the last line of Balmer series and the last line of Lyman series is:
1. \(1\)
2. \(4\)
3. \(0.5\)
4. \(2\)

Subtopic:  Spectral Series |
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Given that the value of the Rydberg constant is \(10^{7}~\text{m}^{-1}\), what will be the wave number of the last line of the Balmer series in the hydrogen spectrum?
1. \(0.5 \times 10^{7}~\text{m}^{-1}\)
2. \(0.25 \times 10^{7} ~\text{m}^{-1}\)
3. \(2.5 \times 10^{7}~\text{m}^{-1}\)
4. \(0.025 \times 10^{4} ~\text{m}^{-1}\)

Subtopic:  Spectral Series |
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In the spectrum of hydrogen, the ratio of the longest wavelength in the Lyman series to the longest wavelength in the Balmer series is:

1. \(\frac{4}{9}\) 2. \(\frac{9}{4}\)
3. \(\frac{27}{5}\) 4. \(\frac{5}{27}\)
Subtopic:  Spectral Series |
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