Instantaneous displacement current of \(2.0~\text A\) is set up in the space between two parallel plates of \(1~\mu \text{F}\)$$ capacitor. The rate of change in potential difference across the capacitor is:
1. \(3\times 10^{6}~\text{V/s}\)
2. \(4\times 10^{6}~\text{V/s}\)
3. \(2\times 10^{6}~\text{V/s}\)
4. None of these

The S.I. unit of displacement current is:
1. Henry
2. Coulomb
3. Ampere
4. Farad

A variable frequency AC source is connected to a capacitor. Then on increasing the frequency:

The charge of a parallel plate capacitor is varying as; \(q = q_{0} \sin\omega t\). The magnitude of displacement current through the capacitor is:
(the plate Area = \(A\), separation of plates = \(d\))
1. \(q_{0}\cos \left(\omega t \right)\)
2. \(q_{0} \omega \sin\omega t\)
3. \(q_{0} \omega \cos \omega t\)
4. \(\frac{q_{0} A \omega}{d} \cos \omega t\)

A larger parallel plate capacitor, whose plates have an area of \(1~\text{m}^2,\) separated from each other by \(1~\text{mm},\) is being charged at a rate of \(25.8~\text{V/s}.\) If the plates have a dielectric constant \(10,\) then the displacement current at this instant is:
1. \(25~\mu\text{A}\)
2. \(11~\mu\text{A}\)
3. \(2.2~\mu\text{A}\)
4. \(1.1~\mu\text{A}\)