\(10~\mu\text F\) capacitor is connected to a \(210~\text V,50~\text{Hz}\) source as shown in the figure. The peak current in the circuit is nearly \((\pi = 3.14)\):
                          
1. \(0.93~\text A\)
2. \(1.20~\text A\)
3. \(0.35~\text A\)
4. \(0.58~\text A\)
Subtopic:  RMS & Average Values |
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The peak voltage of the AC source is equal to:
1. \(1 / \sqrt{2}\) times the rms value of the AC source.
2. the value of voltage supplied to the circuit.
3. the rms value of the AC source.
4. \(\sqrt{2}\) times the rms value of the AC source.
Subtopic:  RMS & Average Values |
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A standard filament lamp consumes \(100\) W when connected to \(200\) V AC mains supply. The peak current through the bulb will be:
1. \(0.707\) A
2. \(1\) A
3. \(1.414\) A
4. \(2\) A
Subtopic:  RMS & Average Values |
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A \(40\) μF capacitor is connected to a \(200\) V, \(50\) Hz AC supply. The rms value of the current in the circuit is, nearly:

1. \(2.05\) A 2. \(2.5\) A
3. \(25.1\) A 4. \(1.7\) A
Subtopic:  RMS & Average Values |
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In an AC circuit, an alternating voltage \(\varepsilon=200 \sqrt{2} \sin (100 t)~\text{V}\) is connected to a capacitor of capacity \(1~\mu \text{F}.\) The RMS value of the current in the circuit is:
1. \(100~\text{mA}\) 2. \(200~\text{mA}\)
3. \(20~\text{mA}\) 4. \(10~\text{mA}\)
Subtopic:  RMS & Average Values | Different Types of AC Circuits |
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The rms value of the potential difference \(V\) shown in the figure is:

       

1. \(\dfrac{V_{0}}{\sqrt{3}}\) 2. \(V_{0}\)
3. \(\dfrac{V_{0}}{\sqrt{2}}\) 4. \(\dfrac{V_{0}}{2}\)
Subtopic:  RMS & Average Values |
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In an AC circuit, the emf (e) and the current (I) at any instant are given respectively by 
e = E0sinω
I = I0sinωt-ϕ 
The average power in the circuit over one cycle of AC is:

1.  EoIo2

2.  EoIo2 sin ϕ

3.  EoIo2 cos ϕ

4.  EoIo

Subtopic:  RMS & Average Values |
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