- 1(current)
Q. No.
1. \(9:16:25\)
2. \(27:32:35\)
3. \(21:24:25\)
4. \(3:4:5\)
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NEET MCQ Books for XIth & XIIth Physics, Chemistry & BiologyA ring is made of a wire having a resistance of \(R_0=12~\Omega.\). Find points \(\mathrm{A}\) and \(\mathrm{B}\), as shown in the figure, at which a current-carrying conductor should be connected so that the resistance \(R\) of the subcircuit between these points equals \(\frac{8}{3}~\Omega\)
| 1. | \(\dfrac{l_1}{l_2} = \dfrac{5}{8}\) | 2. | \(\dfrac{l_1}{l_2} = \dfrac{1}{3}\) |
| 3. | \(\dfrac{l_1}{l_2} = \dfrac{3}{8}\) | 4. | \(\dfrac{l_1}{l_2} = \dfrac{1}{2}\) |
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NEET MCQ Books for XIth & XIIth Physics, Chemistry & BiologyA wire of resistance \(12~ \Omega \text{m}^{-1}\) is bent to form a complete circle of radius \(10~\text{cm}\). The resistance between its two diametrically opposite points, \(A\) and \(B\) as shown in the figure, is:
| 1. | \(0.6\pi~\Omega\) | 2. | \(3\pi ~\Omega\) |
| 3. | \(61 \pi~ \Omega\) | 4. | \(6\pi~\Omega\) |
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NEET MCQ Books for XIth & XIIth Physics, Chemistry & Biology1. 1.2 times, 1.1 times
2. 1.21 times, same
3. both remain the same
4. 1.1 times, 1.1 times
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NEET MCQ Books for XIth & XIIth Physics, Chemistry & Biology
1. 1.5 V
2. 1.0 V
3. 0.5 V
4. 3.2 V
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NEET MCQ Books for XIth & XIIth Physics, Chemistry & Biology- 1(current)
Q. No.
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