A long cylindrical shell is uniformly charged such that the upper half of its curved surface carries a positive surface charge density \(\sigma,\) while the lower half carries an equal negative surface charge density \(-\sigma.\) Which of the following schematic diagrams (not drawn to scale) most accurately represents the resulting pattern of electric field lines around the cylinder?

1.
2.
3.
4.
Subtopic:  Electric Field |
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A thin disc of radius \({b}=2{a}\) has a concentric hole of radius '\(a\)' in it (see figure). It carries a uniform surface charge \('\sigma'\) on it. If the electric field on its axis at height \({'h'}{(h}\ll{a)}\) from its centre is given as:
  

1. \(\dfrac{\sigma h}{2a~\epsilon_0}\)
2. \(\dfrac{\sigma h}{4a~\epsilon_0}\)
3. \(\dfrac{\sigma h}{8a~\epsilon_0}\)
4. \(\dfrac{\sigma h}{a~\epsilon_0}\)
Subtopic:  Electric Field |
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A wire, of length \((L=20~\text{cm}),\) is bent into a semicircular arc. If the two equal halves, of the area, were each to be uniformly charged with charges \({\pm Q,\left[|Q|=10^3 \varepsilon_0\right.}~\text C,\) where \(\varepsilon_0\) is the permittivity (in \(\text{S.I}\) units) of free space] the net electric field at the centre \({O}\) of the semicircular area would be:
 
1. \({(50\times10^3~\text{N/C})~\hat{j}}\)
2. \({(50\times10^3~\text{N/C})~\hat{i}}\)
3. \({(25\times10^3~\text{N/C})~\hat{j}}\)
4. \({(25\times10^3~\text{N/C})~\hat{i}}\)
Subtopic:  Electric Field |
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The region between two concentric spheres of radii '\(a\)' and '\(b\)' , respectively (see figure), has volume charge density \(\rho=\frac{A}{r}\)where \(A\) is a constant and \(r\) is the distance from the centre. At the centre of the spheres is a point charge \(Q\). The value of \(A\) such that the electric field in the region between the spheres will be constant, is:
             
1. \( \frac{Q}{2 \pi a^2} \)
2. \(\frac{Q}{2 \pi\left(b^2-a^2\right)} \)
3. \(\frac{2 Q}{\pi\left(a^2-b^2\right)} \)
4. \(\frac{2 Q}{\pi a^2}\)

Subtopic:  Gauss's Law |
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An electric dipole with dipole moment \(\vec p,\) inclined at an angle \(\theta\) to the \(x\text-\)axis, experiences a torque \(\vec{\tau_1}= \tau \hat k\) in the field \(\vec E_1= E \hat i,\) and a torque \(\vec{\tau_2}=-\vec{\tau_1}\)​ in the field \(\vec E_2 = \sqrt{3}E \hat j.\) The angle \(\theta\) is:

1. \(30^{\circ}\) 2. \(45^{\circ}\)
3. \(60^{\circ}\) 4. \(90^{\circ}\)
Subtopic:  Electric Dipole |
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Four closed surfaces and corresponding charge distributions are shown below.
         
Let the respective electric fluxed through the surfaces be \(\phi_1,\phi_2,\phi_3\) and \(\phi_4.\) Then:
1. \(\phi_1=\phi_2=\phi_3=\phi_4 \)
2. \(\phi_1>\phi_3;~\phi_2<\phi_4 \)
3. \(\phi_1>\phi_2>\phi_3>\phi_4 \)
4. \(\phi_1<\phi_2=\phi_3>\phi_4 \)
Subtopic:  Gauss's Law |
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The mass density of a spherical body is given by \(\rho(r)=\frac{K}{r}\) for \(r\leq R\) and \(\rho(r)=0\) for \(r\leq R,\) where \(r\) is the distance from the centre. The correct graph that describes qualitatively the acceleration \(a\) of a test particle as a function of \(r\) is:
1. 3.
2. 4.

 
Subtopic:  Electric Field |
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A charge \(Q\) is placed at a distance \(\dfrac{a}{2}\) above the centre of the square surface of the edge \(a\) as shown in the figure. The electric flux through the square surface is:

 

1. \(\dfrac{Q}{6{\epsilon_0}}\)

2. \(\dfrac{Q}{2{\epsilon_0}}\)

3. \(\dfrac{Q}{3{\epsilon_0}}\)

4. \(\dfrac{Q}{{\epsilon_0}}\)
 
Subtopic:  Gauss's Law |
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Two identical conducting spheres \(A\) and \(B\) carry an equal charge. They are separated by a distance much larger than their diameters and the force between them is \(F.\) A third identical conducting sphere \(C\) is uncharged. The sphere \(C\) is first touched to \(A\) then to \(B\) and then removed. As a result, the force between \(A\) and \(B\) would be equal to:
1. \(\dfrac{3F}{4}\)

2. \(\dfrac{F}{2}\)

3. \(\dfrac{3F}{8}\)

4. \(F\)
Subtopic:  Coulomb's Law |
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The bob of a simple pendulum has mass \(2~\text{g}\) and a charge of \(5.0~\mu \text{C}\). It is at rest in a uniform horizontal electric field of intensity \(2000~\text{V/m}\). At equilibrium, the angle that the pendulum makes with the vertical is: (take \(g = 10~\text{m/s}^2\))
1. \( \tan ^{-1}(5.0) \)
2. \( \tan ^{-1}(0.5) \)
3. \( \tan ^{-1}(0.2) \)
4. \( \tan ^{-1}(2.0)\)
 

Subtopic:  Electric Field |
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