- 1(current)
Q. No.A uniform rod of length \(l\) is suspended by an end and is made to undergo small oscillations. The time period of small oscillation is \(T\). Then, the acceleration due to gravity at this place is:
| 1. | \(4\pi^2\dfrac{l}{T^2}\) | 2. | \(\dfrac{4\pi^2}{3}\dfrac{l}{T^2}\) |
| 3. | \(\dfrac{8\pi^2}{3}\dfrac{l}{T^2}\) | 4. | \(\dfrac{12\pi^2l}{T^2}\) |
From NCERT
Subtopic: Angular SHM |
To view explanation, please take trial in the course below.
NEET 2026 - Target Batch - Vital
To view explanation, please take trial in the course below.
NEET 2026 - Target Batch - Vital
Please attempt this question first.
Launched MCQ Practice Books
Prefer Books for Question Practice? Get NEETprep's Unique MCQ Books with Online Audio/Video/Text Solutions via Telegram Bot
NEET MCQ Books for XIth & XIIth Physics, Chemistry & BiologyA physical pendulum consists of a uniform rod \(AB\) of mass \(m\) and length \(L,\) suspended from one end \(A\) – so as to rotate freely under gravity. If it is displaced slightly from its mean position, it executes SHM. Let the maximum kinetic energy of the rod be \(E_0.\)
If the time period of a simple pendulum of the same length is \(T_0,\) then the time period of this pendulum is:
If the time period of a simple pendulum of the same length is \(T_0,\) then the time period of this pendulum is:
| 1. | \({\Large\sqrt\frac23}T_0\) | 2. | \({\Large\sqrt\frac{1}{12}}T_0\) |
| 3. | \({\Large\sqrt\frac32}T_0\) | 4. | \(T_0\) |
From NCERT
Subtopic: Angular SHM |
To view explanation, please take trial in the course below.
NEET 2026 - Target Batch - Vital
To view explanation, please take trial in the course below.
NEET 2026 - Target Batch - Vital
Please attempt this question first.
Launched MCQ Practice Books
Prefer Books for Question Practice? Get NEETprep's Unique MCQ Books with Online Audio/Video/Text Solutions via Telegram Bot
NEET MCQ Books for XIth & XIIth Physics, Chemistry & BiologyAn elastic ball is projected vertically upward with a speed \(u,\) and it returns to the ground and rebounds, the motion is periodic with a period \(T.\) A simple pendulum, having a length equal to maximum altitude attained by this ball, would have a time period of:
| 1. | \(T\) | 2. | \(\pi T\) |
| 3. | \(\pi\sqrt2T\) | 4. | \(\dfrac{\pi}{\sqrt 2}T\) |
Subtopic: Angular SHM |
To view explanation, please take trial in the course below.
NEET 2026 - Target Batch - Vital
To view explanation, please take trial in the course below.
NEET 2026 - Target Batch - Vital
Please attempt this question first.
Launched MCQ Practice Books
Prefer Books for Question Practice? Get NEETprep's Unique MCQ Books with Online Audio/Video/Text Solutions via Telegram Bot
NEET MCQ Books for XIth & XIIth Physics, Chemistry & Biology- 1(current)
Q. No.
© 2025 GoodEd Technologies Pvt. Ltd.