- 1(current)
Q. No.| 1. | \(\Delta Q=\Delta U+\Delta W\) |
| 2. | \(\Delta U=\Delta Q+\Delta W\) |
| 3. | \(\Delta U=\Delta Q-\Delta W\) |
| 4. | \(\Delta U+\Delta Q+\Delta W=0\) |
| 1. | work done by the system is \(120~\text{J}.\) |
| 2. | work done on the system is \(120~\text{J}.\) |
| 3. | work done by the system is \(80~\text{J}.\) |
| 4. | work done on the system is \(80~\text{J}.\) |
If an average person jogs, he produces \(14.5 \times10^3\) cal/min. This is removed by the evaporation of sweat. The amount of sweat evaporated per minute (assuming \(1\) kg requires \(580 \times10^3\) cal for evaporation) is:
| 1. | \(0.25\) kg | 2. | \(0.50\) kg |
| 3. | \(0.025\) kg | 4. | \(0.20\) kg |
\(1~\text g\) of water of volume \(1~\text{cm}^3\) at \(100^\circ \text{C}\) is converted into steam at the same temperature under normal atmospheric pressure \(\approx 1\times10^{5}~\text{Pa}.\) The volume of steam formed equals \(1671~\text{cm}^3.\) If the specific latent heat of vaporization of water is \(2256~\text{J/g},\) the change in internal energy is:
| 1. | \(2423~\text J\) | 2. | \(2089~\text J\) |
| 3. | \(167~\text J\) | 4. | \(2256~\text J\) |
| 1. | \(U_0\mathrm{ln}(2)\) | 2. | \(\dfrac12U_0~\mathrm{ln}(2)\) |
| 3. | \(\dfrac13U_0~\mathrm{ln}(2)\) | 4. | \(\dfrac23U_0~\mathrm{ln}(2)\) |
The first law of thermodynamics is a statement of:
1. conservation of heat
2. conservation of work
3. conservation of momentum
4. conservation of energy
- 1(current)
Q. No.
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