- 1(current)
Q. No.Choose the option showing the correct relation between Poisson’s ratio(\(\sigma\)), Bulk modulus(\(B\)), and Modulus of rigidity(\(G\)).
1. \(\mathit{\sigma}{=}\frac{{3}{B}{-}{2}{G}}{{2}{G}{+}{6}{B}}\)
2. \(\mathit{\sigma}{=}\frac{{6}{B}{+}{2}{G}}{{3}{B}{-}{2}{G}}\)
3. \(\mathit{\sigma}{=}\frac{9BG}{{3}{B}{+}{G}}\)
4. \({B}{=}\frac{{3}\mathit{\sigma}{-}{3}{G}}{{6}\mathit{\sigma}{+}{2}{G}}\)
1. \(\mathit{\sigma}{=}\frac{{3}{B}{-}{2}{G}}{{2}{G}{+}{6}{B}}\)
2. \(\mathit{\sigma}{=}\frac{{6}{B}{+}{2}{G}}{{3}{B}{-}{2}{G}}\)
3. \(\mathit{\sigma}{=}\frac{9BG}{{3}{B}{+}{G}}\)
4. \({B}{=}\frac{{3}\mathit{\sigma}{-}{3}{G}}{{6}\mathit{\sigma}{+}{2}{G}}\)
Subtopic: Elasticity |
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NEET MCQ Books for XIth & XIIth Physics, Chemistry & BiologyA uniform rod of mass \(10~\text{kg}\) and length \(6~\text m\) is hanged from the ceiling as shown in the figure. Given the area of the cross-section of rod \(3~\text{mm}^2\) and Young’s modulus is \(2\times10^{11}~\text{N/m}^2.\) The extension in the rod’s length is:
(Take \(g=10~\text{m/s}^2\))
1. \(1~\text{mm}\)
2. \(0.5~\text{mm}\)
3. \(0.25~\text{mm}\)
4. \(1.2~\text{mm}\)
(Take \(g=10~\text{m/s}^2\))
1. \(1~\text{mm}\)
2. \(0.5~\text{mm}\)
3. \(0.25~\text{mm}\)
4. \(1.2~\text{mm}\)
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NEET MCQ Books for XIth & XIIth Physics, Chemistry & BiologyTwo blocks, one with a mass of \(2~\text{kg}\) and the other with a mass of \(1.14~\text{kg},\) are suspended by steel and brass wires, respectively, as shown in the figure. Given Young's moduli for steel and brass as \(2\times10^{11}~\text{N}/\text{m}^2\) and \(1\times10^{11}~\text{N}/\text{m}^2\) respectively, what is the change in the length for the steel wire?
| 1. | \(3.2 ~\mu \text{m}\) | 2. | \(1.6 ~\mu \text{m}\) |
| 3. | \(0.8 ~\mu \text{m}\) | 4. | \(4.8 ~\mu \text{m}\) |
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NEET MCQ Books for XIth & XIIth Physics, Chemistry & Biology- 1(current)
Q. No.
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