A satellite is in a circular orbit around a planet, orbiting with a speed of \(2\) km/s. What is the minimum additional velocity that should be given to it, perpendicular to its motion, so that it escapes?
                 
1. \(2\) km/s 2. \(2\sqrt2\) km/s
3. \(2(\sqrt2-1)\) km/s 4. \(2(\sqrt2+1)\) km/s
Subtopic:  Escape velocity |
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Two large uniform solid spheres each of mass \(M,\) radius \(R\) are in contact with each other. If a particle is launched from a point on the surface of a sphere, diametrically opposite to the contact point, its escape velocity will be:
1. \(\sqrt{\dfrac{4GM}{R}}\) 2. \(\sqrt{\dfrac{4GM}{3R}}\)
3. \(\sqrt{\dfrac{8GM}{3R}}\) 4. \(\sqrt{\dfrac{2GM}{3R}}\)
Subtopic:  Escape velocity |
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The acceleration due to gravity, \(g\), near a spherically symmetric planet's surface decreases with height, \(h\) according to the relation:
\(g(h)= g_s-k\cdot h\), where \(h\ll\) the radius of the planet.
The escape speed from the planet's surface is:

1. \(\dfrac{g_s}{2\sqrt k}\) 2. \(\dfrac{g_s}{\sqrt k}\)
3. \(\dfrac{2g_s}{\sqrt k}\) 4. \(g_s\sqrt{\dfrac{2}{k}} \)
Subtopic:  Escape velocity |
To view explanation, please take trial in the course below.
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NEET MCQ Books for XIth & XIIth Physics, Chemistry & Biology