Object \(A\) has half the kinetic energy as that of object \(B.\) The object \(B\) has half the mass as that of the object \(A.\) The object \(A\) speeds up by \(1~\text{ms}^{-1}\) and then has the same kinetic energy as that of object \(B.\) The initial speed of object \(A\) is nearly: (Take \(\sqrt2\cong1.4\))
1. \(0.5~\text{ms}^{-1}\)
2. \(1~\text{ms}^{-1}\)
3. \(2.5~\text{ms}^{-1}\)
4. \(4.8~\text{ms}^{-1}\)
Subtopic:  Work Energy Theorem |
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An object moving along a horizontal \(x\text-\)direction with kinetic energy \(10~\text J\) is displaced through \(x=\left(3\hat{i}\right)\text{m}\) by the force \(\vec{{{F}}}=\left(-2\hat{i}+3\hat{j}\right)~\text N.\) The kinetic energy of the object at the end of the displacement \(x\) is:
1. \(10~\text J\) 2. \(16~\text J\)
3. \(4~\text J\) 4. \(6~\text J\)
Subtopic:  Work Energy Theorem |
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A bullet from a gun is fired on a rectangular wooden block with velocity \(u\). When bullet travels \(24\) cm through the block along its length horizontally, velocity of bullet becomes \(u/3\). Then it further penetrates into the block in the same direction before coming to rest exactly at the other end of the block. The total length of the block is:
1. \(30\) cm
2. \(27\) cm
3. \(24\) cm
4. \(28\) cm
Subtopic:  Work Energy Theorem |
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Consider a drop of rainwater having a mass of \(1~\text{gm}\) falling from a height of \(1~\text{km}\). It hits the ground with a speed of \(50~\text{m/s}\). Take \(g\)  as constant with a value \(10~\text{m/s}^2.\) The work done by the
(i) gravitational force and the
(ii) resistive force of air is:

1. \((\text{i})~1.25~\text{J};\) \((\text{ii})~-8.25~\text{J}\)
2. \((\text{i})~100~\text{J};\) \((\text{ii})~8.75~\text{J}\)
3. \((\text{i})~10~\text{J};\) \((\text{ii})~-8.75~\text{J}\)
4. \((\text{i})~-10~\text{J};\) \((\text{ii})~-8.75~\text{J}\)

Subtopic:  Work Energy Theorem |
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A block of mass \(10\) kg, moving in the \(x\)-direction with a constant speed of \(10\) ms–1 is subjected to a retarding force \(F=0.1x\) J/m during its travel from \(x = 20\) m to \(30\) m. Its final kinetic energy will be:
1. \(475\) J
2. \(450\) J
3. \(275\) J
4. \(250\) J
Subtopic:  Work Energy Theorem |
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A body of mass \(1\) kg is thrown upwards with a velocity \(20\) ms-1. It momentarily comes to rest after attaining a height of \(18\) m. How much energy is lost due to air friction?
(Take \(g=10\) ms-2)
1. \(20\) J
2. \(30\) J
3. \(40\) J
4. \(10\) J

Subtopic:  Work Energy Theorem |
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A ball is thrown vertically upward. It has a speed of 10m/sec when it has reached one-half of its maximum height. How high does the ball rise? Take g = 10 m/s2:

1. 5m

2. 15m

3. 10 m

4. 20 m

Subtopic:  Work Energy Theorem |
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A stone is tied to a string of length 'l' is whirled in a vertical circle with the other end of the string as the centre. At a certain instant of time, the stone is at its lowest position and has a speed 'u'. The magnitude of the change in velocity as it reaches a position where the string is horizontal (g being acceleration due to gravity) is:

1. u2g

2. uu22g

3. 2 g

4. 2(u2g)

Subtopic:  Work Energy Theorem |
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A child is sitting on a swing. Its minimum and maximum heights from the ground are \(0.75\) m and \(2\) m, respectively. Its maximum speed will be: (Take \(g=10\) m/s2)
1. \(10\) m/s
2. \(5\) m/s
3. \(8\) m/s
4. \(15\) m/s

Subtopic:  Work Energy Theorem |
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The bob of a simple pendulum having length l, is displaced from the mean position to an angular position θ with respect to vertical. If it is released, then the velocity of the bob at the lowest position will be:

1. 2gl(1-cosθ)

2. 2gl(1+cos θ)

3. 2gl cosθ

4. 2gl

Subtopic:  Work Energy Theorem |
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