A rigid rod is placed against the wall as shown in the figure. When the velocity at its lower end is \(10\) ms-1 and its base makes an angle \(\alpha=60^\circ\) with horizontal, then the vertical velocity of its end \(\mathrm{B}\) (in ms-1) will be:
                  

1. \(10\sqrt{3}\) 2. \(\frac{10}{\sqrt{3}}\)
3. \(5\sqrt{3}\) 4. \(\frac{5}{\sqrt{3}}\)
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