- 1(current)
Q. No.| 1. |  |
2. |  |
| 3. |  |
4. |  |
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NEET MCQ Books for XIth & XIIth Physics, Chemistry & BiologyThe position of a particle as a function of time \(t\), is given by;
\(x(t)=a t+b t^2-c t^3\)
where \(a\), \(b\) and \(c\) are constants. When the particle attains zero acceleration, then its velocity will be:
1. \( a+\frac{b^2}{4 c} \)
2. \( a+\frac{b^2}{c} \)
3. \( a+\frac{b^2}{3 c} \)
4. \( a+\frac{b^2}{2 c}\)
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NEET MCQ Books for XIth & XIIth Physics, Chemistry & Biology1. \(100\) ms-2
2. \(200\) ms-2
3. \(300\) ms-2
4. \(400\) ms-2
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NEET MCQ Books for XIth & XIIth Physics, Chemistry & Biology1. \(125\) m
2. \(500\) m
3. \(250\) m
4. \(400\) m
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NEET MCQ Books for XIth & XIIth Physics, Chemistry & Biology| Statement I: | We can get displacement from the acceleration-time graph. |
| Statement II: | We can get acceleration from the velocity-time graph. |
| 1. | Both Statement I and Statement II are correct. |
| 2. | Both Statement I and Statement II are incorrect. |
| 3. | Statement I is correct and Statement II is incorrect. |
| 4. | Statement I is incorrect and Statement II is correct. |
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NEET MCQ Books for XIth & XIIth Physics, Chemistry & Biology- 1(current)
Q. No.
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