[Cr(NH3)6]3+ is paramagnetic ,while Ni(CN)42- is diamagnetic because:

1. Electrons in the 3d orbitals remain unpaired in Ni(CN)42-
2. Electrons in the 3d orbitals remain unpaired in [Cr(NH3)6]3+
3. Electrons in the 3p orbitals remain unpaired in [Cr(NH3)6]3+
4. Electrons in the 3p orbitals remain unpaired in Ni(CN)42-

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The correct electronic configuration of the central atom in K4FeCN6  based on crystal field theory is:

1. \(e^4 ~t_{2 g}^2 \) 2. \(t_{2 g}^4 ~e_g^2 \)
3. \(t_{2 g}^6 ~e_g^0 \) 4. \(e^3 ~t^3_{2g}\)
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Which among the following is a diamagnetic complex?

1. NiCN42-

2. CuCl42-

3. CoF63-

4. NiCl42-

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The correct splitting diagram of d orbitals in an octahedral crystal field is:

1. 2.
3. 4.  
None of these.
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An example of a sigma bonded organometallic compound is:

1. Ruthenocene                 

2. Grignard's reagent

3. Ferrocene                     

4. Cobaltocene

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Of the following complex ions, the diamagnetic complex is:

1. [Ni(CN)4]2-                       

2. [CuCl4]2-

3. [CoF6]3-                           

4. [NiCl4]2-

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The hybridisation of [FeF6]3- is:

1. sp3d2 2. d2sp3
3. dsp3 4. sp3
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The electronic configuration that represents the maximum magnetic moment is:

1. d3

2. d2

3. d8

4. d6(high spin)

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The low spin complex among the following is:

1. \(\mathrm{Fe}(\mathrm{CN})_6^{3-} \) 2. \(\mathrm{Co}\left(\mathrm{NO}_2\right)_6^{3-} \)
3. \(\mathrm{Mn}(\mathrm{CN})_6^{3-} \) 4. All of the above
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The hybridisation of Ni in the complex [Ni(CN)4]2- is:
(Atomic number of Ni = 28)

1. dsp2                               

2. sp3

3. d2sp2                             

4. d2sp3

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