The compound which on reduction with ${\mathrm{LiAlH}}_4$ gives two diffrent alcohols:

1. ${\mathrm{CH}}_3{\mathrm{COOCH}}_3$                         

2.  ${\mathrm{CH}}_3{\mathrm{COOC}}_2{\mathrm{H}}_5$

3. ${\mathrm{CH}}_3{\mathrm{COCH}}_3$                           

4.  ${\mathrm{CH}}_3\mathrm{CHO}$

HCHO and HCOOH are distinguished by treating with:

1. Tollens reagent

2. NaHCO₃

3. Fehling's Solution

4. Benedict Solution

Lacrymator or tear gas is:

1. C₆H₅COCl                               

2. C₆H₅OC₆H₅

3. C₆H₅COCH₂Cl                         

4. C₆H₅COCH₃

Formaldehyde can be distinguished from acetaldehyde by:

1. Fehling's solution                     

2. Schiff's reagent

3. Ammonia                               

4. Ammoniacal ${\mathrm{AgNO}}_3$

The correct acidity order of the following is:

1. (III)>(IV)>(II)>(I)                       

2. (IV)>(III)>(I)>(II)

3. (III)>(II)>(I)>(IV)                       

4. (II)>(III)>(IV)>(I)  

Acetone reacts with iodine (I₂) to form iodoform in the presence of      

1. CaCO₃   

2. NaOH     

3. KOH     

4. MgCO₃

Generally Aldehydes behave as:

1. Oxidising agent

2. Reducing agent

3. Dehydration agent

4. Oxidizing as well as reducing agent

Compound (A) C₅H₁₀O forms a phenyl hydrazone and gives negative Tollen's and iodoform tests. Compound (A) on reduction gives n-pentane. Compound (A) is:

1. a primary alcohol

2. an aldehyde

3. a ketone

4. a secondary alcohol 

RCOOH $\to$RCH₂OH. This mode of reduction of an acid to alcohol can be affected only by:

1. Zn/HCl

2. Na-alcohol

3. aluminium isopropoxide and isopropyl alcohol

4. LiAlH₄

Ethyl ester $\underset{\mathrm{Excess}}{\overset{{\mathrm{CH}}_3\mathrm{MgBr}}{\to }}$ P. the product P will be: 

1. 

2. 

3.

4.