The capacity of a parallel plate condenser is 15 μF, when the distance between its plates is 6 cm. If the distance between the plates is reduced to 2 cm, then the capacity of this parallel plate condenser will be?
1. 15 μF
3. 30 μF
4. 45 μF
5. 60 μF

The capacity of a parallel plate capacitor with no dielectric substance but with a separation of 0.4 cm is 2 μF. The separation is reduced to half and it is filled with a dielectric substance of value 2.8. The final capacity of the capacitor is 

1. 11.2 μF

2. 15.6 μF

3. 19.2 μF

4. 22.4 μF

Two insulated metallic spheres of 3 μF and 5 μF capacitances are charged to 300 V and 500V respectively. The energy loss, when they are connected by a wire is 

1. 0.012 J

2. 0.0218 J

3. 0.0375 J

4. 3.75 J

A charge of 40 μC is given to a capacitor having capacitance C = 10 μF. The stored energy in ergs is 

1. 80 × 10^–6

2. 800

3. 80

4. 8000

A parallel plate capacitor has plate area A and separation d. It is charged to a potential difference V₀. The charging battery is disconnected and the plates are pulled apart to three times the initial separation. The work required to separate the plates is 

1. $\frac{3{\epsilon }_{0}A{V}_0^2}{d}$

2. $\frac{{\epsilon }_{0}A{V}_0^2}{2d}$

3. $\frac{{\epsilon }_{0}A{V}_0^2}{3d}$

4. $\frac{{\epsilon }_{0}A{V}_0^2}{d}$

The electric field between the plates of a parallel plate capacitor when connected to a certain battery is E₀. If the space between the plates of the capacitor is filled by introducing a material of dielectric constant K without disturbing the battery connections, the field between the plates shall be 

1. K E₀

2. E₀

3. $\frac{E_0}{K}$

4. None of the above

If the distance between parallel plates of a capacitor is halved and dielectric constant is doubled then the capacitance 

1. Decreases two times

2. Increases two times

3. Increases four times

4. Remain the same

If there are n capacitors each of capacitance C in parallel connected to V volt source, then the energy stored is equal to 

1. CV

2. $\frac{1}{2}nC{V}^2$

3. CV²

4. $\frac{1}{2n}C{V}^2$

The unit of electric permittivity is 

1. Volt/m²

2. Joule/coulomb

3. Farad/m

4. Henry/m

The work done in placing a charge of 8 × 10^–18 coulomb on a condenser of capacity 100 micro-farad is 

1. 32× 10^–32 Joule

2. 16 × 10^–32 Joule

3. 3.1 × 10^–26 Joule

4. 4 × 10^–10 Joule