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Q. No.What is the correct relationship between changes in enthalpy and internal energy within the following options?
1. \(\Delta \mathrm{H}+\Delta \mathrm{U}=\Delta \mathrm{nR} \)
2. \(\Delta \mathrm{H}=\Delta \mathrm{U -\Delta n_gRT}\)
3. \(\Delta \mathrm{H}=\Delta \mathrm{U+\Delta n_gRT }\)
4. \(\Delta \mathrm{H} -\Delta \mathrm{U=-\Delta n_gRT}\)
Subtopic: Enthalpy & Internal energy |
81%
From NCERT
NEET - 2023
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Consider the following reaction:
\(\mathrm{2H_2(g) + O_2(g) \rightarrow 2H_2O(g) \Delta_rH^\circ = -483.64 kJ. }\)
What is the enthalpy change for the decomposition of one mole of water?
\(\mathrm{2H_2(g) + O_2(g) \rightarrow 2H_2O(g) \Delta_rH^\circ = -483.64 kJ. }\)
What is the enthalpy change for the decomposition of one mole of water?
| 1. | 120.9 kJ | 2. | 241.82 kJ |
| 3. | 18 kJ | 4. | 100 kJ |
Subtopic: Thermochemistry |
87%
From NCERT
NEET - 2023
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If it’s discovered that a certain non-spontaneous reaction becomes spontaneous if the temperature is lowered, then which of the following must be true:
1. ∆S is negative and ∆H is positive.
2. ∆S is negative and ∆H is negative.
3. ∆S is positive and ∆H is positive.
4. ∆S is positive and ∆H is negative.
1. ∆S is negative and ∆H is positive.
2. ∆S is negative and ∆H is negative.
3. ∆S is positive and ∆H is positive.
4. ∆S is positive and ∆H is negative.
Subtopic: Spontaneity & Entropy |
51%
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The specific heat of tungsten is 0.03 cal/g-°C. If a 50-gram sample of tungsten absorbs 100 calories of heat, the change in temperature of the sample will be:
1. 76 °C
2. 55 °C
3. 67 °C
4. 62 °C
1. 76 °C
2. 55 °C
3. 67 °C
4. 62 °C
Subtopic: Cp & Cv |
78%
From NCERT
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One mole of an ideal gas at 300 K is expanded isothermally from 1 L to 10 L volume. \(\Delta U\) for this process is:
(Use R = 8.314 J K–1 mol–1)
(Use R = 8.314 J K–1 mol–1)
| 1. | 1260 J | 2. | 2520 J |
| 3. | 5040 J | 4. | 0 J |
Subtopic: First Law of Thermodynamics |
79%
From NCERT
NEET - 2022
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The work done when 1 mole of gas expands reversibly and isothermally from a pressure of 5 atm to 1 atm at 300 K is:
(Given log 5 = 0.6989 and R = 8.314 J K-1 mol-1)
1. zero J
2. 150 J
3. +4014.6 J
4.-4014.6 J
Subtopic: First Law of Thermodynamics |
71%
From NCERT
NEET - 2022
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Subtopic: 2nd & 3rd Law of Thermodynamics |
85%
From NCERT
NEET - 2022
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Tin is obtained from cassiterite by reduction with coke. Use the data given below to determine the minimum temperature (in K) at which the reduction of cassiterite by coke would take place at -
\(298 \mathrm{~K}: \Delta_{f} H^{\circ}\left[\mathrm{SnO}_{2}(s)\right]=-581.0 kJ \mathrm{~mol}^{-1}\)
\(\begin{aligned} &\Delta_{f} H^{\circ}\left[\left(CO_{2}\right)(g)\right]=-394.0 k J mol^{-1} \\ &S^{\circ}\left[\mathrm{SnO}_{2}(s)\right]=56.0 JK^{-1} \mathrm{~mol}^{-1} \\ &S^{\circ}[\operatorname{Sn}(s)]=52.0 \mathrm{~J} \mathrm{~K}^{-1} \mathrm{~mol}^{-1} \\ &S^{\circ}[C(s)]=6.0 \mathrm{JK}^{-1} \mathrm{~mol}^{-1} \\ &S^{\circ}\left[\mathrm{CO}_{2}(g)\right]=210.0 \mathrm{~J} \mathrm{~K}^{-1} \mathrm{~mol}^{-1} \end{aligned}\)
(Assume that the enthalpies and the entropies are temperature independent)
1. 298 K
2. 450 K
3. 935K
4. 900 K
\(298 \mathrm{~K}: \Delta_{f} H^{\circ}\left[\mathrm{SnO}_{2}(s)\right]=-581.0 kJ \mathrm{~mol}^{-1}\)
\(\begin{aligned} &\Delta_{f} H^{\circ}\left[\left(CO_{2}\right)(g)\right]=-394.0 k J mol^{-1} \\ &S^{\circ}\left[\mathrm{SnO}_{2}(s)\right]=56.0 JK^{-1} \mathrm{~mol}^{-1} \\ &S^{\circ}[\operatorname{Sn}(s)]=52.0 \mathrm{~J} \mathrm{~K}^{-1} \mathrm{~mol}^{-1} \\ &S^{\circ}[C(s)]=6.0 \mathrm{JK}^{-1} \mathrm{~mol}^{-1} \\ &S^{\circ}\left[\mathrm{CO}_{2}(g)\right]=210.0 \mathrm{~J} \mathrm{~K}^{-1} \mathrm{~mol}^{-1} \end{aligned}\)
(Assume that the enthalpies and the entropies are temperature independent)
1. 298 K
2. 450 K
3. 935K
4. 900 K
Subtopic: Spontaneity & Entropy |
71%
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One mole of an ideal gas at 900 K undergoes two reversible processes, I followed by II, as shown below. If the work done by the gas in the two processes is same, the value of \(ln {V_3 \over V_2}\) is:
(U: internal energy, S: entropy, p: pressure, V: volume, R: gas constant)
(Given : molar heat capacity at constant volume, \(C_{v,m}\) of the gas is \({ 5 \over 2 }R\))
(U: internal energy, S: entropy, p: pressure, V: volume, R: gas constant)
(Given : molar heat capacity at constant volume, \(C_{v,m}\) of the gas is \({ 5 \over 2 }R\))
| 1. | 5 | 2. | 10 |
| 3. | 0.1 | 4. | 0.5 |
Subtopic: First Law of Thermodynamics |
55%
From NCERT
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Match List I with List II.
Choose the correct answer from the options given below:
1. \(\text { A-IV, B-II, C-III, D-I }\)
2. \(\text { A-I, B-II, C-III, D-IV }\)
3. \(\text { A-II, B-III, C-IV, D-I }\)
4. \(\text { A-IV, B-III, C-II, D-I }\)
| List-I (Process) | List-II (Conditions) | ||
| A. | Isothermal process | I. | No heat exchange |
| B. | Isochoric process | II. | Carried out at constant temperature |
| C. | Isobaric process | III. | Carried out at constant volume |
| D. | Adiabatic process | IV. | Carried out at constant pressure |
1. \(\text { A-IV, B-II, C-III, D-I }\)
2. \(\text { A-I, B-II, C-III, D-IV }\)
3. \(\text { A-II, B-III, C-IV, D-I }\)
4. \(\text { A-IV, B-III, C-II, D-I }\)
Subtopic: Thermodynamics' Properties and process |
86%
From NCERT
NEET - 2024
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