8.29 :  Given the standard electrode potentials,

K+/K=-2.93V,Ag+/Ag=0.80V,Hg2+/Hg=0.79VMg2+/Mg=-2.37V.Cr3+/Cr=-0.74V

Arrange these metals in their increasing order of reducing power.

NEETprep Answer:
The lower the electrode potential, the stronger is the reducing agent. Therefore, the increasing order of the reducing power of the given metals is Ag < Hg < Cr < Mg < K.