Q.4. Uθ of combustion of methane is – X kJ mol-1. The value of Hθ

(i) =Uθ

(ii) >Uθ

(iii) <Uθ

(iv) = 0

NEETprep Answer:
Since 
Hθ=Uθ+ngRTandUθ=-XkJmol-1,
Hθ=-X+ngRT.Hθ<Uθ
Therefore, alternative (iii) is correct.