Ncert Exercises & Solutions

Arrange the halogens $F_{2}, {Cl}_{2}, {Br}_{2}, I_{2}$ , in order of their increasing reactivity with alkanes:

1.	$I_{2} < {Br}_{2} < {Cl}_{2} < F_{2}$	2.	${Br}_{2} < {Cl}_{2} < F_{2} < I_{2}$
3.	$F_{2} < {Cl}_{2} < {Br}_{2} < I_{2}$	4.	${Br}_{2} < I_{2} < {Cl}_{2} < F_{2}$

HINT- High electronegativity means high reactivity with alkanes

EXPLAINATION (1)

Alkane react with

F_{2}

is vigorously and with

I_{2}

the reaction is too slow that it requires a catalyst. It is because of high electronegativity of fluorine. Reactivity decreases with decrease in electronegativity and electronegativity decreases down the group.

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