Ncert Exercises & Solutions

11.20 How are the following conversions carried out?

(i) Propene → Propan-2-ol.

(ii) Benzyl chloride → Benzyl alcohol.

(iii) Ethyl magnesium chloride → Propan-1-ol.

(iv) Methyl magnesium bromide → 2-Methylpropan-2-ol.

(i) If propene is allowed to react with water in the presence of an acid as a catalyst,

then propan-2-ol is obtained.

C H_{3} — C H = C H_{2} + H_{2} O ⇌ C H_{3} — C H — C H_{2}

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P r o p e n e O H

P r o p a n - 2 o l

(ii) If benzyl chloride is treated with NaOH (followed by acidification) then benzyl

alcohol is produced.

(iii) When ethyl magnesium chloride is treated with methanal, an adduct is the

produced which gives propan-1-ol on hydrolysis.

(iv) When methyl magnesium bromide is treated with propane, an adduct is the product

which gives 2-methylpropane-2-ol on hydrolysis.