Identify the products A and B formed in the following reaction


CH3CH2CH=CHCH3+HClCH2CH2CHCH3
|
Cl
(2-chloropentane)
+CH3CH2CHCH2CH3
|
(3-Chloropentane)

The carbocation formed from compound (A) is slightly less stable than carbocation

jeading to the formation of compound (B) therefore the amount of 2-chloropentane (B) will

be little bit more than that of 3- chloropentane (A).