Ncert Exercises & Solutions

Highest oxidation state of manganese in fluoride is +4(\(Mn 𝐹_ 4\)) but highest oxidation state in oxides is +7(\(𝑀 𝑛_ 2 𝑂_ 7\)) because:

1.	Fluorine is more electronegative than oxygen
2.	Fluorine does not possess d orbitals
3.	Fluorine stabilises lower oxidation state
4.	In covalent compounds, fluorine can form single bond only while oxygen forms double bond

Hint: Oxygen can make a double bond

Explanation:
Highest oxidation state of manganese in fluoride is +4(\(MnF_4\)) but highest oxidation state in oxides is +7( \(Mn_2O_7\) ). The reasonis that in covalent compounds fluorine can form single bond while oxygen forms double bond.

NEET Information

courses

Company

Botany Questions

Chemistry Questions

Physics Questions

Zoology Questions