Ncert Exercises & Solutions

The correct graphical representation of relation between ln k and 1/T is:

1.		2.
3.		4.

HINT: Use Arrhenius Equation.

Explanation:

$According$ $to$ $Arrhenius$ $equation,$
$k = {Ae}^{- E_{a} / RT}$
$Taking$ $natural$ $\log$ $on$ $both$ $side$
$lnk = \ln$ $(A \cdot e^{- \frac{E_{a}}{RT}})$
$\ln$ $k = \ln$ $A - \frac{E_{a}}{RT}$
$\ln$ $k = - \frac{- E_{a}}{R} \times \frac{1}{T} + \ln$ $A$

This equation can be related to the equation of the straight line as shown below:

$y =$ $mx$ $+$ $c$
From the graph, it is very clear that the slope of the plot = $\frac{- E_{a}}{R}$ and intercept= In A.

Hence, option first is the correct answer.

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