In which of the following compounds, the carbon marked with an asterisk is most electronegative?

1. CH3-CH2-*CH2-CH3

2. CH3-*CH=CH-CH3

3. CH3-CH2-C*CH

4. CH3-CH2-CH=*CH2

Hint: Percentage of s character directly proportional to electronegativity
 
The electronegativity of carbon atoms depends on their state of hybridization. More s-character more is the electronegativity.
 
sp3<sp2<sp
25%s33%s50%s
 
Thus, sp-carbon has the highest electronegativity, i.e., option (3) (CH3-CH2-C*CH) is correct.