Ncert Exercises & Solutions

7.42 The pH of a sample of vinegar is 3.76. Calculate the concentration of hydrogen ion in it.

Given, pH
= 3.76
It is known that,

$pH = - \log [H^{+}]$
$\Rightarrow \log [H^{+}] = - pH$
$\Rightarrow [H^{+}] = antilog (- pH)$
$= antilog (- 3.76)$
$= 1.74 \times 10^{- 4} M$

Hence, the concentration of hydrogen ion in the given sample of vinegar is $1.74 \times 10^{- 4} M$